Explain the folling data regarding artificial gravity. Just explain why these formulas were needed to ultimately find the artificial gravity(4.26 m/s^2) Linear AccelerationStep 1a = roGivena = (243 x 10-2 m)(4, 18 rad/s)?Angular velocityw = 40 rotations per 60 secondsa = 4. 26 m/s(4.659 kgix(10.1 m/s)F =243 x10 mF = 198. 6 Nradius r= 243 cm = 243 x 102 mForce of the wheelMass m = 4.659 kgF = maF = (4. 659 kg) (4. 26 m/s?)Step 4Step 2F = 198. 6 NAnswerForce on the wheelv = 10.1 m/sSolutionF = myF=ma = 198.6 NAngular velocity= 4.659 kg)x(10.1 m/s)?243 x10" mF = 198. 6 NF= mv?/r=198.6 N40 rotations60s40 x2e radians60 s0 = 4. 18 rad/sStep 4Linear velocityv = rov = (243 x 10-2 m) (4. 18 rad/s)Answerv = 10. 1 m/sv = 10.1 m/sF=ma = 198.6 NF= mv?/r=198.6 N

The artificial gravity is also known as the acceleration. This is related to gravity because it…

Answered: Explain the folling data regarding…

Explain the folling data regarding artificial gravity. Just explain why these formulas were needed to ultimately find the artificial gravity(4.26 m/s^2)

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter8: Rotational Motion

Section: Chapter Questions

Problem 6STP

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Question

Explain the folling data regarding artificial gravity. Just explain why these formulas were needed to ultimately find the artificial gravity(4.26 m/s^2)

Linear Acceleration
Step 1
a = ro
Given
a = (243 x 10-2 m)(4, 18 rad/s)?
Angular velocityw = 40 rotations per 60 seconds
a = 4. 26 m/s
(4.659 kgix(10.1 m/s)
F =
243 x10 m
F = 198. 6 N
radius r= 243 cm = 243 x 102 m
Force of the wheel
Mass m = 4.659 kg
F = ma
F = (4. 659 kg) (4. 26 m/s?)
Step 4
Step 2
F = 198. 6 N
Answer
Force on the wheel
v = 10.1 m/s
Solution
F = my
F=ma = 198.6 N
Angular velocity
= 4.659 kg)x(10.1 m/s)?
243 x10" m
F = 198. 6 N
F= mv?/r=198.6 N
40 rotations
60
s
40 x2e radians
60 s
0 = 4. 18 rad/s
Step 4
Linear velocity
v = ro
v = (243 x 10-2 m) (4. 18 rad/s)
Answer
v = 10. 1 m/s
v = 10.1 m/s
F=ma = 198.6 N
F= mv?/r=198.6 N

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