EXAMPLES Find an equation of the tangent line to the parabola y--&x+9 at the point (2.-3). SOLUTION From the previous example, we know the derivative of Rx)=x²-x+9 at the number a is F(a)-2a-8. Therefore the slope of the tangent line at (2.-3) is F(2)-2(2)-8-. Thus an equation of the tangent line, shown in the figure, is -()-[

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter3: Linear And Nonlinear Functions
Section: Chapter Questions
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EXAMPLE 5
Find an equation of the tangent line to the parabola y=x²-8x + 9 at the point (2, -3).
SOLUTION From the previous example, we know the derivative of f(x) = x² - 8x + 9 at the number a is f'(a) = 2a - 8. Therefore the slope of the tangent line at (2, -3) is f'(2) = 2(2) - 8 = [
equation of the tangent line, shown in the figure, is
or
. Thus an
Transcribed Image Text:V EXAMPLE 5 Find an equation of the tangent line to the parabola y=x²-8x + 9 at the point (2, -3). SOLUTION From the previous example, we know the derivative of f(x) = x² - 8x + 9 at the number a is f'(a) = 2a - 8. Therefore the slope of the tangent line at (2, -3) is f'(2) = 2(2) - 8 = [ equation of the tangent line, shown in the figure, is or . Thus an
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