// Example 8.27b void Func(int a[], int & r) { int i; int induction = r; for (i = 0; i < 100; i += 2) { a[i] = induction; a[i+1] = induction; induction++; } } Write The compiler generate assembly code from example 8.27b.
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// Example 8.27b
void Func(int a[], int & r) {
int i;
int induction = r;
for (i = 0; i < 100; i += 2) {
a[i] = induction;
a[i+1] = induction;
induction++;
}
}
Write The compiler generate assembly code from example 8.27b.
Step by step
Solved in 2 steps
- Translate C program to Pep/9 assembly language. /C code for 6.19a#include <stdio.h>char myChar;char toLower(char ch) { if ((ch >= ’A’) && (ch <= ’Z’)) { return ch + ’a’ - ’A’; } else { return ch; }}int main () { scanf(”%c”, &myChar); printf(”%c\n”, toLower(myChar)); return 0;}SumDouble.java [1 13 14 14 27 28 * Logic problem for CS 170. @author * @version */ public class SumDouble /** * Complete the function sumDouble(). * Given two int values, return their sum. * Unless the two values are the same; * then return double their sum. * Some examples sumDouble (1, 2) returns 3 sumDouble (3, 2) returns 5 sumDouble (2, 2) returns 8 @param a is the first int value. * @param b is the second int value. * @return their sum or double their sum if equal. */ public int sumDouble(int a, int b) { // Complete the sumDouble method here.) Consider the following C code snippet. void swap(int *xp, int *yp) { int temp = *xp; *xp = *yp; *yp = temp; } int findMinimum(int arr[], int N) { // variable to store the index of minimum element int min_idx = 0; int min_E = arr[min_idx]; // Traverse the given array for (int i = 1; i < N; i++) { // If current element is smaller than min_idx then update it if (arr[i] < min_E) { min_idx = i; min_E = arr[min_idx]; } } return min_idx; } /* Function to sort an array using selection sort*/ void selectionSort(int arr[], int n) { int i, min_idx; // One by one move boundary of unsorted subarray for (i = 0; i < n-1; i++) { // Find the minimum element in unsorted array min_idx = findMinimum(&arr[i], n-i); // Swap the found minimum element with the first element if(min_idx != 0) swap(&arr[min_idx+i], &arr[i]); } }…
- java: // Class to do MergeSort and QuickSort on int arrays and test them public class MergeQuickSorts { // Create a main to test MergeSort and QuickSort for // three cases - Sorted Aray, Reverse Sorted Array, Random Array // Each array should be size 50 // For the sorted array use the entries 1, 2, 3......50 // For the reverse sorted array use the entries 50, 49, 48.....1 // For the random array use ints between 1 and 50 inclusive, duplicates allowed // For each of the 6 sorts print the array before and after the sort // and show clearly which sort is being done public static void main(String[] args) { }2. JAVA Programming Arrays a1, a2… are populated as shown; display a[i] for each calls to arr; if a[i] less than or equal to 0 display a message indicating those conditions public static void arr(int[] a) { //Add the missing loop a[i] = a[i + 1] + a[i - 1]; // display a[i] } } a1 = 3, 7 a2 = 4, 7, 4, 2, 10, 9 a3 = 1, 5, 0, 0, 5, 0 a4 = 13, 0, -4, -2, 0, -1 a5 = 2, 4, 6, 8, 16int c[2][3]; int a[2][3] ={ {5}, {1,2} }; int b[2][3] = { 2,4,6,8} for( int i=0; i<2 ;i++)5. for( int j=0; j<3 ; j++) c[i] [j] = 3 * ( a[i] [j] + b[i] [j] ); program with c++
- Instruction: Explain the function of the program line by line thoroughly.Program: #include <iostream>using namespace std; void sort(int a[], int num){ for(int i =0; i < num; i++){ for(int j = i+1; j < num; j++){ if(a[j] < a[i]) a[i] = a[i] + a[j] -(a[j] = a[i]); } }} int main(){ int n; cout<<"Enter number of integers: "; cin >> n; int *a = new int[n]; // Dynamic memory allocation using new. int val; for(int i =0; i < n; i++){ cout << " Enter integer No. "<< i+1 << ": "; cin >> val; a[i] = val; } sort(a,n); cout << "\nSorted Integers: "; for(int i =0; i < n; i++) cout << a[i] << " "; return 0;}main.cpp:4:17: error: 'string' has not been declared 4 | void KMPSearch(string pat, string txt) main.cpp:4:29: error: string' has not been declared 4 | void KMPSearch(string pat, string txt) Aununun main.cpp:31:25: error: string' has not been declared 31 | void computelPSArray(string pat, int M, int[] lps) main.cpp:31:50: error: expected or . before lps' 31 | void computeLlPSArray(string pat, int M, int[] lps) main.cpp:55:8: error: expected :' before 'static' 55 | public static void Main() main.cpp:61:2: error: expected ;' after class definition 61 | } | main.cpp: In member function 'void GFG::KMPSearch(int, int)': main.cpp:6:15: error: request for member Length' in 'pat', which is of non-class type 'int' 6 | int M = pat.Length; main.cpp:7:15: error: request for member Length' in txt’, which is of non-class type 'int' int N = txt.Length; main.cpp:8:6: warning: structured bindings only available with -std3c++17' or (-std=gnu++17' 8 | int[] lps new int[M];C. Using the starter code please modify in Java public class L08 { public static void main(String[] args) { // TO DO: // Test your radix sort implementation here } // TO DO: // Implement // NOTE: You can assume that all strings in the array have the same length public static void radixSort(String[] array) { } //////* HELPER METHODS *////// private static String[] generateStringArray(int wordLen, int arrLen) { String[] array = new String[arrLen]; for(int i = 0; i < arrLen; i++) { StringBuilder sb = new StringBuilder(); for(int j = 0; j < wordLen; j++) { sb.append((char)('a' + Math.random() * ('z' - 'a' + 1))); } array[i] = sb.toString(); } return array; } private static void displayStringArray (String[] array) { for(String s : array) { System.out.println(s); } } private static boolean isSortedInNondescendingOrder(String[] array) { for(int i = 1; i < array.length; i++) { if (array[i].compareTo(array[i-1]) < 0) { return false; } } return true; } } Implement radix sort for…
- Using recursion in C++ print all the elements of the array given below, char cArr[5] = {'a', 'e', 'i', 'o', 'u'}; Attach the code and output.Q2-Consider the following code fragment. i-m-1; j=n; v=a[n]; while (true) { do i=i+1; while( a[i] v); i(i >= j) break; x=a[i]; a[i]=a[j]; a[j]=x; } x=a[i]; a[i] = a[n]; a[n] =x; a) Translate the above code into three address statements: b) Construct a control flow graph of the three address statements generated in part a)C++ and the focus is on Pass by Reference: The following steps are essentially under the same problem but in order to complete a step, the previous must be completed first. For example, Step #3 cannot be completed unless Step #1 and #2 have been conducted. And, Step #4 cannot be performed if the previous three steps have not been solved. Step #1) See the RAND with 5473 Step #2) create an array of 12 integer elements with the values from the rand () that range from 100 to 999. Hint see discussion of random, range and offset. Step #3) create a function that returns the value of the maximum entry Step #4) now create a second function that returns the index of the element that contains the maximum value.