Example 3: The charge flowing through the imaginary surface in Fig. 7 is 0.16 C every 64 ms. Determine the curent in amperes.

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter28: Current And Resistance
Section: Chapter Questions
Problem 65PQ
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1 %AV |11.
V;IV
then total charge which crosses the section in time dt is dq = nAevdt. Since current is the rate of flow of charge,
it is given as
dg nAevdt
= nAev
dt
dt
Current density, J == nev ampere/metre
Assuming a normal current density J= 1.55 x 10° A/m?, n = 10° for a copper conductor and e =1.6 x 10-19
coulomb, we get
1.55 x 10 = 1029 x 1.6 x 10-19 × v
v = 9.7 x 10-5 m/s
Example 3:
The charge flowing through the imaginary surface in Fig. 7 is 0.16 C every 64 ms. Detemine the current in
amperes.
Example 4:
Determine the time required for 4 x 101 electrons to pass through the imaginary surface in Fig. 7 if the current
is 5 mA
Example 5:
A conductor material has a free-electron density of 1024 electrons per metre', when a voltage is applied, a constant
drift velocity of 1.5x10° meter/second is attained by the electrons. If the cross-sectional area of the material is 1
cm?, calculate the magnitude of the current. (Answer: I=0.24 A)
Example 6:
A copper wire of are 5mm2 has a current of SmA following through it. Calculate the current density?
4. Resistance:
The flow of charge through any material encounters an opposing force similar in many respects to mechanical
friction This opposition, due to the collisions between electrons and between electrons and other atoms in the
material, which converts electrical energy into another form of energy such as heat, is called the resistance of
the material. The unit of measurement of resistance is the ohm, for which the symbol is
letter omega
the capital Greek
The resistance of any material with a uniform cross-sectional area is determined by the following four factors
(see Fig. 8):
1. Material
2. Length
3. Cross-sectional area
4. Temperature
At a fixed temperature of 20°C (room temperature), the resistance is related to the other three factors by
6/1
40
56414
II
Transcribed Image Text:1 %AV |11. V;IV then total charge which crosses the section in time dt is dq = nAevdt. Since current is the rate of flow of charge, it is given as dg nAevdt = nAev dt dt Current density, J == nev ampere/metre Assuming a normal current density J= 1.55 x 10° A/m?, n = 10° for a copper conductor and e =1.6 x 10-19 coulomb, we get 1.55 x 10 = 1029 x 1.6 x 10-19 × v v = 9.7 x 10-5 m/s Example 3: The charge flowing through the imaginary surface in Fig. 7 is 0.16 C every 64 ms. Detemine the current in amperes. Example 4: Determine the time required for 4 x 101 electrons to pass through the imaginary surface in Fig. 7 if the current is 5 mA Example 5: A conductor material has a free-electron density of 1024 electrons per metre', when a voltage is applied, a constant drift velocity of 1.5x10° meter/second is attained by the electrons. If the cross-sectional area of the material is 1 cm?, calculate the magnitude of the current. (Answer: I=0.24 A) Example 6: A copper wire of are 5mm2 has a current of SmA following through it. Calculate the current density? 4. Resistance: The flow of charge through any material encounters an opposing force similar in many respects to mechanical friction This opposition, due to the collisions between electrons and between electrons and other atoms in the material, which converts electrical energy into another form of energy such as heat, is called the resistance of the material. The unit of measurement of resistance is the ohm, for which the symbol is letter omega the capital Greek The resistance of any material with a uniform cross-sectional area is determined by the following four factors (see Fig. 8): 1. Material 2. Length 3. Cross-sectional area 4. Temperature At a fixed temperature of 20°C (room temperature), the resistance is related to the other three factors by 6/1 40 56414 II
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