Example 2: > Value of N, represents size of Arr 5 ->
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- CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;Q1 function myFunc() { let a = 10; if (true) { Q3 } } let a = 5; console.log(a); Q4 console.log(a); Q2 const square = num => num * num; console.log(square(3) + 5); myFunc(); let x = 30; let y "200"; console.log(x+y); const nums = [10, 20, 8, 17]; nums.filter(e=> e > 10); console.log(nums); Q5 const nums = [30, 35, 42, 20, 15]; console.log(nums.every (num => num > 20)); January 15Outputs of the following: void main () { int M[3]; int "ptr; ptr=M; *ptr=100; ptr++; "ptr=200; ptr=&M[2]; *ptr=300; for (int n=0; n<3; n++) cout <Answer in JavaScript Tim while preparing for his CAT exam, was studying the topic Number Systems. He encountered a loving da question: Given a number N, find the number of pairs (cy) where both x and y are less than N and Highent Common Factor(HCF) of x and y is 1. You have to solve the question for him. Note: 0 can be included within the pairs Input Specification: Input: The number N from which the pairs (x,y) should be obtained Output Specification: Return the total number of pairs Example 1: input1: 4 Output: 9 Explanation: The pairs can be (1,0) ,(0,1) (1,1) (1,2) (2,1) (0, 3) (3,1) (2,3) (0,2) So, a total of 9 pairsMatch the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxif L1={ab,b} L2={abb,bb} then L1L2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}JAVA LANGUAGE CODE Postfix Calculator by CodeChum Admin One good implementation of computing infix expressions is to transform them to postfix and then evaluate via the postfix expression. Infix expressions is the common way of writing arithmetic expressions. The binary operator come between them as shown below: 2 * 5 + 9 - 10 / 20 In postfix expressions, the operands come first before the operator: 2 5 * 9 + 10 20 / - A stack can be used to evaluate postfix expressions. The operands are pushed onto the Stack and when an operator is found two operands are popped and the operation is performed and finally the result is pushed back onto the Stack. The final answer will be the lone element of the Stack. Input The first line contains a positive integer n representing the number of postfix expressions. What follows are n postfix expressions themselves. 5 10 20 + 30 15 2 * + 100 20 30 + / 90 20 10 + + 0 / 9 3 - 10 + 2 * Output A single line containing the result of…4. A={3,4}, B={4,5}. An B= AUB= A-B= A OB= AXB=In the C programming language, if all function prototypes are listed at the top of your code, outside and above all functions, you do not need to worry about the order of the function definitions within the code. True Falseint f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)A = [1 1; 1 -1];b = [80; 20]; A_inverse = inv(A);x = A\b; disp('A inverse is');disp(A_inverse);disp(['x1 is ', num2str(x(1)), ' and x2 is ', num2str(x(2))]); if isequal(round(x), [50; 30]) disp('Success');else disp('Incorrect: Please try again');end. Output matlab. .SEE MORE QUESTIONS