Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW=60.05) was added to a 1-liter volumetric flask, and the flask was filled to the mark with distilled water. A portion of the resulting solution was added to a conductance cell (k = 1.25 cm¹), and the conductance was found to be 416 µS. Calculate the dissociation constant Ka of acetic acid. AºH+ = 349.8 Scm²/mole and A CH3COO = 41 Scm²/mole

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
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Chapter10: Effect Of Electrolytes On Chemical Equilibria
Section: Chapter Questions
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Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW =60.05) was added to a 1 –liter volumetric flask, and the flask was filled to the mark with distilled water. A portion of the resulting solution was added to a conductance cell (k = 1.25 cm-1), and the conductance was found to be 416 μS. Calculate the dissociation constant Ka of acetic acid. ΛoH+= 349.8 Scm2/mole   and ΛoCH3COO- = 41 Scm2/mole

Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW =60.05) was added to a 1-liter
volumetric flask, and the flask was filled to the mark with distilled water. A portion of the resulting
solution was added to a conductance cell (k = 1.25 cm³¹), and the conductance was found to be
416 µS. Calculate the dissociation constant Ka of acetic acid. AºH+ = 349.8 Scm²/mole
and
A°CH3COO = 41 Scm²/mole
Transcribed Image Text:Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW =60.05) was added to a 1-liter volumetric flask, and the flask was filled to the mark with distilled water. A portion of the resulting solution was added to a conductance cell (k = 1.25 cm³¹), and the conductance was found to be 416 µS. Calculate the dissociation constant Ka of acetic acid. AºH+ = 349.8 Scm²/mole and A°CH3COO = 41 Scm²/mole
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