Evaluate the following integrals using a trigonometric substitution. Hint: complete the square for part b. x² a) √ 1²2 da S dx b) / x² + 6x dx (Note: A clever way to evaluate the first integral is to add and subtract one to the numerator or use long division. No points will be given for these approaches.) 1+x² [² x² +1 -1 1+x² - / (1+2-1+₂) dx = x-tan-¹x+C 1+x² 1+x² dx =

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