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esc STARTING AMOUNT ! AMB 0¹ F1 . X 3662 @ F2 1 # 80 F3 15 How many moles of aluminum are required to completely react with 107 6.00 M H₂SO according to the balanced chemical reaction: 2 Al(s) + 3 H₂SO (aq) → Al₂(SO),(aq) + 3 H₂(g) 0.428 ADD FACTOR NOV 7 × ( ) 0.0374 mL H₂SO M H₂SO Q 98.08 F4 1 % mol H₂ ļ F5 2 g H₂SO Question 1 of 4 tv 3 6.022 x 1023 mol Al . 107 9 F6 ANSWER g Al mol H₂SO mol Al₂(SO₂), S I MacBook Air & 428 ← 1000 F7 g H₂ 6.00 0.001 A DII mL of RESET g Al₂(SO), LH₂SO, FB D 0.963 B DD F9 . . 30 F10 .

esc STARTING AMOUNT ! AMB 0¹ F1 . X 3662 @ F2 1 # 80 F3 15 How many moles of aluminum are required to completely react with 107 6.00 M H₂SO according to the balanced chemical reaction: 2 Al(s) + 3 H₂SO (aq) → Al₂(SO),(aq) + 3 H₂(g) 0.428 ADD FACTOR NOV 7 × ( ) 0.0374 mL H₂SO M H₂SO Q 98.08 F4 1 % mol H₂ ļ F5 2 g H₂SO Question 1 of 4 tv 3 6.022 x 1023 mol Al . 107 9 F6 ANSWER g Al mol H₂SO mol Al₂(SO₂), S I MacBook Air & 428 ← 1000 F7 g H₂ 6.00 0.001 A DII mL of RESET g Al₂(SO), LH₂SO, FB D 0.963 B DD F9 . . 30 F10 .

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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can you help me and plug it in in the correct form i keep doing it and its saying im wrong

< esc STARTING AMOUNT :0 F1 X 3.662 -0 F2 30 # 80 F3 15 How many moles of aluminum are required to completely react with 107 6.00 M H₂SO according to the balanced chemical reaction: 4 0.428 NOV 7 ADD FACTOR $ x( ) X 2 0.0374 mL H₂SO M H₂SO 4 Q F4 Al(s) + 98.08 % 1 mol H₂ 0 F5 3 H₂SO (aq) →→ Al(SO),(aq) + 3 H₂(g) 2 g H₂SO Question 1 of 4 atv 3 6.022 x 1023 mol Al 107 ņ @ F6 ANSWER g Al mol H₂SO mol Al₂(SO₂), MacBook Air 428 & 1000 F7 4 IM 2 g H₂ 6.00 0.001 A mL of RESET g Al₂(SO), LH₂SO F8 D 0.963 4 * (((( C F9 C A 30 F10 W
Transcribed Image Text:< esc STARTING AMOUNT :0 F1 X 3.662 -0 F2 30 # 80 F3 15 How many moles of aluminum are required to completely react with 107 6.00 M H₂SO according to the balanced chemical reaction: 4 0.428 NOV 7 ADD FACTOR $ x( ) X 2 0.0374 mL H₂SO M H₂SO 4 Q F4 Al(s) + 98.08 % 1 mol H₂ 0 F5 3 H₂SO (aq) →→ Al(SO),(aq) + 3 H₂(g) 2 g H₂SO Question 1 of 4 atv 3 6.022 x 1023 mol Al 107 ņ @ F6 ANSWER g Al mol H₂SO mol Al₂(SO₂), MacBook Air 428 & 1000 F7 4 IM 2 g H₂ 6.00 0.001 A mL of RESET g Al₂(SO), LH₂SO F8 D 0.963 4 * (((( C F9 C A 30 F10 W
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