eorder the following to melts faster to slowest to melt
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Reorder the following to melts faster to slowest to melt
1. Ice with Sand
2. Ice with nothing
3. Ice with Sugar
4. Ice with Salt
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Solved in 2 steps
- Java Script There is a single operator in JavaScript, capable of providing the remainder of a division operation. Two numbers are passed as parameters. The first parameter divided by the second parameter will have a remainder, possibly zero. Return that value. Examples remainder(1, 3) → 1 remainder(3, 4) → 3 remainder(-9, 45) → -9 remainder(5, 5) → 0 Notes The tests only use positive and negative integers. Don't forget to return the result.Flexibility exercises stretch your muscles and can help your body stay flexible. These exercises may not improve your endurance or strength, but being flexible gives you more freedom of movement for other exercise as well as for your everyday activities. Flexibility is a Fitness and we cannot give the actual implementation for the methods muscleTargeted () and calorieLoss () as we don't know the actual Anaerobic exercise. The descripton () method returns the string Flexibility is uncomfortable and it takes time, so people don't like to do it. Note that Flexibility is a good candidate to be abstract class. Define classes Yoga and TaiChi, which are Flexibility fitness exercises. Use the table above to define the classes. The classes also have: • @0verride public String description () returns the name of the respective classes.In your own words, what is encapsulation?
- : Design and implement a text-based Minesweeper game. Minesweeper is the classicsingle-player computer game where an NxN grid has B mines (or bombs) hidden across the grid. Theremaining cells are either blank or have a number behind them. The numbers reflect the number ofbombs in the surrounding eight cells. The user then uncovers a cell. If it is a bomb, the player loses.If it is a number, the number is exposed. If it is a blank cell, this cell and all adjacent blank cells (up toand including the surrounding numeric cells) are exposed. The player wins when all non-bomb cellsare exposed. The player can also flag certain places as potential bombs. This doesn't affect gameplay, other than to block the user from accidentally clicking a cell that is thought to have a bomb.(Tip for the reader: if you're not familiar with this game, please play a few rounds on line first.)Please see the snip for the detail. Note: The polygon have to rotate clockwise in same also counterclock wise have to rotate: here is my code it have issue it only rotate to clockwise but in same time have to rotate to the counterclockwise too but it not plesase fix it or write from new. my code: import turtle as t import math class CenteredPolygon: def __init__(self, n, size, center=(0, 0), pen=None, **kwargs): self.numsides = n self.size = size self.center = center self.corners = [] self.pen = pen if pen is not None else self.init_pen(**kwargs) self.draw() def init_pen(self, **kwargs): pen = t.Turtle() for key, value in kwargs.items(): try: f = getattr(pen, key) f(value) except Exception as e: print(e) return pen def set_corners(self) -> list: p = self.pen p.pu() p.goto(self.center) for i…Email me the answers to the following questions. If you are not familiar with Peg Solitaire, then look it up online. Peg Solitaire is a game consisting of a playing board with 33 holes together with 32 pegs. In the picture above, the hole in the center is empty and the remaining holes contain pegs. The goal is to remove all the pieces except one, which should be in the center. A piece can be removed by jumping an adjacent piece over it into an empty hole. Jumps are permitted horizontally or vertically, but not diagonally. Your assignment consists of one required part, plus one extra credit part: 1. Explain (in words) why Breadth First Search and Iterative Deepening are not good methods for this problem.
- Java problem. While out on a standard run we notice that our radar is picking up someone following us. In the hopes of losing them, we look for a nearby debris field to hide in. We notice one not too far away, but we need to make sure that we can get to the middle of the debris field to be properly hidden. Our radar shows the debris field in 2D, so we can visually check if we can make it to the center, but that takes too long. We want a program that will let us know if there is a path from the outside of the debris field to the center. In order to solve this problem, we must think recursively. Create a recursive algorithm that determines if a path exists from the outside of the debris field to the center. The debris field is always square (n by n) and n will always be greater than 1, and always odd. You can enter the debris field from any of the outside spaces, and you simply need to return true if a path exists, and false if a path does not exist. For movement you can only go up,…Complete the convert() method that casts the parameter from a double to an integer and returns the res Note that the main() method prints out the returned value of the convert() method. Ex: If the double value is 19.9, then the output is: 19 Ex: If the double value is 3.1, then the output is: 3 512334.3517088.qx3zqy7 LAB ACTIVITY 1 public class LabProgram { INM + ∞ 2 25.20.1: LAB: Write convert() method to cast double to int 3 public static int convert (double d) { /* Type your code here */ 4 5 6 7 } 8 public static void main(String[] args) { 9 System.out.println (convert (19.9)); 10 11 12} } System.out.println(convert(3.1)); LabProgram.javaMake a MAZE game on Spyder, giving the user to choose their route. Each route will have either doors or obstacles that the user will solve or use logic to complete. Use a random function so the obstacles change with a new try. The user needs to get out of the Maze in three tries or he loses a life. The user will be asked a question whether they want to try it again or skip the level. Need help with the code!! Thank you
- Complete the searching and sorting algorithms in ModuleOne and ModuleTwo of the modules package. Test all sorting algorithms in AlgorithmsTest. You must build everything from scratch and cannot use any methods in other Java packages to make your algorithm. PLEASE PLEASE FILL AND FINISHES THE MODULETWOComplete the recursive drawBoxes() method so that it will draw all of the boxes in the image below. It currently only draws the first and smallest Box. Feel free to use a different shape if you do not like boxes.What is encapsulation?Clarify with help of example?