2- Solve and analyze the following parallel RLC circuit? What feature does it show? Find the length of the impedance, the high currents in the voltage arms, the welding current, and the power coefficient of the circuit? 500s R: 0,6H 2uF 3uF 220 V SOHZ
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Q: 500s R: 0,6H> 2µF 3µF 220 V SOHZ
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Q: Solve and analyze the following parallel RLC circuit? What feature does it show? Find the impedance…
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- A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.A 22-k resistor and a 0.02-F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V Select one: a. 0.501 ms b. 0.66 ms c. 0.44 ms d. 0.70 ms
- An inductance coil consumes 500W of power at 10A and 110V and 60HZ. Determine the resistance and the inductance of the coilI need answer with explaination In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltageAn inductor and a resistor are in series with a sinewave voltage source. The frequency is set so that the inductive reactance is equal to the resistance. If the frequency is increased, then options: Voltage across the inductor= Source Voltage Voltage across the inductor> Voltage across the resistor Voltage across the inductor= Voltage across the resistor Voltage across the resistor > Voltage across the inductor
- A series R–L–C circuit comprises a 5µF capacitor, a 4ohm resistor and a variable inductance L. The supply voltage is 10∠0◦ V at a frequency of 159.1 Hz. The inductance is adjusted until the p.d. across the 4 ohm resistanceis a maximum. Determine for this condition (a) the value of inductance, (b) the p.d. across each component and (c) the Q-factor of the circuit.Attenuators with Capacitances Construct the circuit in Figure. Use R1 = 1kohm, C1-39nF. R2=3.9kohm. Vi C1 R1 HH R2 Vo What is the effect of the capacitor C1 in the circuit? You may use equations to help explain your answer.For R1=9000, R2=2000, R3=6000, R4=5000, C1=0.006, C2=D0.002 & 11=0.007 A in the shown circuit, obtain the energy stored in each capacitor under dc conditions. C2 R4 ŽR3 ER2 ŽRI C1= Energy stored in C1= Energy stored in C2=
- 1. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.A 6-ohm resistor is connected in parallel with a 300 uF capacitor and the circuit is supplied by a 10A 60Hz current source. Find the instantaneous current through the resistor and the capacitor.Show final Circuit