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- Choose the best explanation for why -OH and -NH peaks are often broad singlets in a ¹H NMR spectrum. A) The greater electronegativity difference in the N-H or O-H bond compared to a C-H bond makes the peak broader. B) The greater mass involved in the N-H or O-H bond compared to a C-H bond makes the peak broader. C) The hydrogen nuclei on the carbon next to the -OH or -NH are too far away to impact the multiplicity. D) Protons in OH or NH groups are acidic enough to rapidly exchange between different molecules, so the coupling to vicinal hydrogens is not clearly observed.How can IR spectroscopy distinguish between 1-hexyne, 2-hexyne, and 3-hexyne?1,3-Dibromobutane has the 1H NMR spectrum shown below. Map each hydrogen atom in the molecule of 1,3-dibromobutane with its corresponding peak number.
- An oxidation reaction was conducted using cyclohexanol and NaOCl to make cyclohexanone. How can we know that the NMR for cyclohexanone is in fact cyclohexanone( the NMR for cyclohexanone is not labeled). Analyze the spectra to prove its identity along with the NMR of the starting material which is the spectra labeled cyclohexanol below.9) What would be the difference between the 4 alcohols in IR? They all show O-H, C-H sp3, and C-H aromatic bonds. The only way to tell which one is used would be by comparing the fingerprint regions to published IR spectra of each alcohol. Alcohol 2 has an aldehyde C-H group that could be seen between 2700-2800 and 2800-2900 cm-1 Only alcohol 3 will show O-H bond around 3300 cm-1 Only alcohol 1 will show C=C aromatic bonds around 1600 cm-1 10) Assuming 5.0 mL of alcohol 2 was used and 2.2 g of the product was isolated, what is the percent yield for this reaction? The product has a molar mass of 198.00 g/mol. 11) How could the percent yield be increased for this reaction? Add NaOH to neutralize the product as it forms Add a catalyst such as H2SO4 to help speed up the reaction Add a catalyst such as HCl to help speed up the reaction Cool the reaction on ice to increase the rate of reaction 12) Is there another way that the product of this reaction…In the box provided, write the IR frequency or range of frequencies that would best distinguish between the two compounds shown. Specify which compound (A or B) will display a band at this frequency in its IR spectrum. Bond O-H (alcohol) O-H (carboxylic acid) N-H Stretching frequency (cm-¹) 3200-3650 2500-3300 3100-3550 2850-3000 3000-3100 C-H (alkane) C-H (alkene) C-H (alkyne) C=C 2100-2250 C=C 1600-1680 C=O (aldehyde/ketone) 1630-1820 C=O (ester) 1735-1800 1700-1725 C=O (carboxylic acid) C-O 1000-1250 A 3300 B OH Intensity Medium, broad Strong, broad Medium Medium Medium to strong Weak to medium Weak Weak to medium Strong Strong Strong Strong (Choose the most prominent frequency. Do not include units in your answer. Use only the frequencies listed above. If there is more than one correct answer, only give one.) Write the letter of the compound, followed by the range of frequencies, separated by a comma. Example. "A,1600-1850". IR frequency or range of frequencies: cm-1 Previous Next
- How do you interpret these IR and 1H NMR spectra without having a molecular formula?Look at the structure of ethyl acetate in your notebook. In which region of the 13C spectrum of ethyl acetate would you NOT expect any peaks? a.0 - 50 ppm b.50 - 100 ppm c.100 - 160 ppm d.160 - 220 ppmLabel all relevant peaks that are above the fingerprint region (>1500 cm-1) in all the IR spectra given below with the functional group that those peaks are representative of (make sure not to forget the aldehyde C–H bonds, which many IR charts do not list). Based on the table you completed with predicted Diagnostic IR peaks for each compound, and based on the IR spectra you had labeled, match each compound with its spectrum.