During the 1950s the wholesale price for chicken for a country fell from 25e per pound to 14e per pound, while per capita chicken consumption rose from 21.5 pounds per year to 27 pounds per year. Assume that the demand for chicken depended linearly on the pric (a) Construct a linear demand function q(p), where p is in cents (e.g., use 14e, not $0.14). Then, find the revenue function. R(p). R(P) = (b) What wholesale price for chicken would have maximized revenues for poultry farmers? e per pound Second derivative test: Your answer above is a critical point for the revenue function. To show it is a maximum, calculate the second derivative of the revenue function. R"(p)=

ENGR.ECONOMIC ANALYSIS
14th Edition
ISBN:9780190931919
Author:NEWNAN
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Chapter1: Making Economics Decisions
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During the 1950s the wholesale price for chicken for a country fell from 25c per pound to 14c per pound, while per capita chicken consumption rose from 21.5 pounds per year to 27 pounds per year. Assume that the demand for chicken depended linearly on the price.
(a) Construct a linear demand function q(p), where p is in cents (e.g., use 14c, not $0.14).
Then, find the revenue function. R(p).
R(p) =
(b) What wholesale price for chicken would have maximized revenues for poultry farmers?
¢ per pound
Second derivative test:
Your answer above is a critical point for the revenue function. To show it is a maximum, calculate the second derivative of the revenue function.
R"(p)=
Transcribed Image Text:During the 1950s the wholesale price for chicken for a country fell from 25c per pound to 14c per pound, while per capita chicken consumption rose from 21.5 pounds per year to 27 pounds per year. Assume that the demand for chicken depended linearly on the price. (a) Construct a linear demand function q(p), where p is in cents (e.g., use 14c, not $0.14). Then, find the revenue function. R(p). R(p) = (b) What wholesale price for chicken would have maximized revenues for poultry farmers? ¢ per pound Second derivative test: Your answer above is a critical point for the revenue function. To show it is a maximum, calculate the second derivative of the revenue function. R"(p)=
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