Draw the equivalent circuit model and switching characteristics of the device which is used in high frequency and low power application
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- What is Basic Circuit elementAmong its products is the power transducer. The product is an electrical isolation transducer of single-phase active and reactive power measurement, complete isolation between input and output signals. It is designed to measure power, reactive power and power factor. The product is widely used in electricity, communications, railways, industrial control and other fields. The transducer weights 0.7-pound, 1-500-volt, 0.5-700 A, the size is 76mmx32mmx2inch. The response time of the transducer is 250 ms. (a) 1. What is the volume of the transducer in cubic m? 2. How many transducers can be packed in box of 1m X 0.5 m X Qm? 3. If the factory produces 500 transducer per hour, how many minutes are needed to produce 50 kg of the transducer? 4. If the production line needs maintenance every 100,000 transducer. Find to the nearest integer how many weeks are needed to be sent to maintenance if the production rate is 100 transducer/min which operates 8 hours/ day and 5 days / week.A. For the circuit diagram shown below, determine and sketch the output voltage (Vout). 1_ohm GaAs 1 ohm 1_ohm Ge Si A 1_ohm. 6_Vpeak w. Vout)
- 1. During turn-on and turn-off of a power transistor supplying a resistive load, the voltage and current variations are as shown in the figure below as idealized linear changes with time, where the V is off-state voltage and I is on-state current. Determine the mean switching power-loss due to switching at a frequency of 10 kHz. 300 V- - 200 A 200 A -300 V 1 us Time 2 us Time Turn-on Turn-off1. During turn-on and turn-off of a power transistor supplying a resistive load, the voltage and current variations are as shown in the figure below as idealized linear changes with time, where the V is off-state voltage and I is on-state current. Determine the mean switching power-loss due to switching at a frequency of 10 kHz. 300 V - 200 A 200 A- -300 V 1 us Time 2 us Time Turn-on Turn-off 2. A single-phase single-diode (half wave) rectifier is connected to a 240 V, 50 Hz AC supply. Neglecting the diode volt drop, derive the instantaneous load current equation, determine the current waveform, mean load voltage, and the mean load current for a load of a. Pure resistor of 5 Ohm b. An inductance of 0.1 H in series with 10 Ohm resistor. (clue : B = 265° or 14.72 ms) 3. A single-phase full bridge fully controlled thyristor rectifier ( a = 45° ) is supplied by grid (supply) voltage of V, = 220 V (rms value). Assume that the load is represented by a constant de (flat) current, Ia = 10 A.…Design the power supply using diode components. This power supply sholud have 2 outputs. 12Vdc and 5Vdc. Input 240 Vac Supply i. Draw the circuit diagram ii. Bill of material/components that will be used iii. Teh output waveform for each stage
- Draw a schematic diagram of a full-wave bridge power supply.A resistor Ra is in series with a voltage source Va. Draw the circuit. Label the voltage across the combination as v and the current as i. Draw and label the volt–ampere characteristic (i versus v).2. Write about two applications for a series circuit, (Think about the different electronics at home or at work), and some of the advantages and disadvantages?
- What is the approximate value of the collector voltage in the given figure below for each of these troubles? a) R1 open b) R2 open c) RE open d) RC open e) Collector-emitter openIdentify the right statement relating to Zener impedance a. O b. O c. O d. the ratio of change of current to the change in input voltage in the breakdown region the ratio of change of voltage to the change in input power in the breakdown region None of the above the ratio of change of voltage to the change in input current in the breakdown region1-The output voltage of an emitter follower is a-In phase with Vin . b-Much greater than Vin. c-180° out of phase. d-Generally much less than Vin • 2-The ac emitter resistance of an emitter follower a-Equal the de emitter resistance. b-Is larger than the load resistance. c-Is B times smaller than the load resistance. d-Is usually less than the load resistance. 3-A common-base amplifier can be used when a-Matching low to high impedance. b-A voltage gain without a current gain is required. c-A high- frequency amplifier is needed. d-All of the above. 4-If the voltage generator is 5 mV in an emitter follower, the output voltage across the load is closest to a-5 mV. b-150mV. c-0.25 mV. d-0.5 mV.