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- A charge of 36.3 nC is transferred to a neutral copper ball of radius 4.35 cm. The ball is not grounded. The excess electrons spread uniformly on the surface of the ball. What is the number density (number of electrons per unit surface area) of excess electrons on the surface of the ball?Why do most objects tend to contain nearly equal numbers of positive and negative charges?A positively charged It'd attracts a small piece of cork. (a) Can we conclude that the cork is negatively charged? (b) The rod repels another small piece of cork. Can we conclude that this piece is positively charged?
- (a) Would life be different if the electron were positively charged and the proton were negatively charged? (b) Does the choice of signs have any bearing on physical and chemical interactions? Explain your answers.(a) What is the direction of the total Coulomb force on q in Figure 18.46 if q is negative, qa= qcand both are negative, and qb= qcand both are positive? (b) What is the direction of the electric field at the center of the square in this situation?1. What are the basic postulates of the charge model?
- 3. Figure 1 shows electrie field lines near two charges. a. What is the sign of cach charge? b. Do the charges have the same magnitude? If not, which has greater magnitude? c. What type of interaction occurs between the two charges? Figure 1A 12µC charge is located 40 cm to the left of a -2µC charge. What is the magnitude and direction of the Coulomb force on the negative charge? wered of Recall that k = 8.99 x 10° Nm?Cc2 slion O a. 7.2 N to the right O b. 6 N to the right O c. 2.4 N, to the right Od. 1.35 N to the left e. 2.4 C, to the right in Rie logatod 20 cm to tho loft of an3. A small piece of rubber from shoe has a charge -10uC and an area rug with charge 4 uC are separated by a distance of 10cm: a. Is the Electrostatic force repulsive or attractive ? Explain b. Determine the electrostatic force using the Coulomb's Law equation and the Coulomb's Electrostatic Force Calculator. Step 1: List all the measurements given: Q, = µC ,Q;= µC ,d= cm, k=9.0x 10°NM/C Step 2: Substitute : F =(9.0x 10°NM/C )( µC)( µC) 7 ( cm) elect Step 3: Use Coulomb's Electrostatic Force Calculator To get the final answer F !! elect C. If the -10uC charge were halved and the distance between the charges halved, did the electrostatic increase or decrease? Justify your answer
- I. Multiple Choice. Write the letter of the correct answer on the space provided before the number. _1. The law stating that "force is directly proportional to the product of charges and inversely proportional to the square of separation between them" is called_ A. Newton's law B. Coulomb,s law 2. Two positive charges Q, = 16 C and Q2 = 4 C, separated by a diameter of 3 m will produce a force of A. 40.0 N 3. Electric charges under the action of electric forces is called A. electrostatics B. electric flux C. electric field 4. Two charges 1 C and -4 C exists in air. What is the direction of the force? A. away from 10 S. Find the force, in µN, betweeniwo,ckarges mhen theyere brought in Contest and 4 em apart. The charges are 2 nC and –1 nC. C. Gauss's law D. Ohm's law B. 41.1 N C. 42.3 N D. 42.7 N D. electric field lines B. awa- from -4 C C. from 1C to –4 C n from -4C to 1 ↑Suppose you have a dipole that’s free to move in any way, including rotate. And there’s an object with charge Q a distance raway. That distance r would be much larger than d, the distance of the dipole. A. Would the dipole end up attracted to the charge, repelled, or neither? B. Would the chargeQbe attracted, repelled, or neither to thedipole? C. Does the answer to parts A and B depend on the sign of Q?1. A simple diagram of the electric field around an alpha particle is shown below. State the feature of the diagram that shows that the electric field gets weaker as the distance from the alpha particle increases. 2. Charges qA and qB are in a vacuum and have a distance of 15 cm between their centres. Charge qc is placed on the line joining qA and qB, at a point where it experiences zero net force. This point is 5.0 cm from charge qA, as shown in the diagram below: 9A 5.0 cm ● 9c 15 cm [This diagram is not drawn to scale.] Using proportionality, calculate the ratio of charge q to charge qA- 9B