Does the pedigree below appear to show a dominant trait or a recessive trait? What patterns did you see that support your conclusion? Key to the pedigree image: Squares represent males, circles represent females. A horizontal line connecting two shapes represents a cross (a male/female couple that produces offspring). Vertical lines coming down from a cross leads to offspring of the cross. Black-shaded shapes show individuals displaying the phenotype being studied. Shapes that are not shaded-in represent individuals who do not display the phenotype being studied.
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- To interpret the above pedigree, there are some pedigree rules that you need to know. Squares are males, and circles are females. Horizontal lines connecting shapes in the middle indicate that two individuals have offspring together. Vertical lines indicate a parent-offspring relationship. Siblings are connected with a horizontal line *above* the shapes (check out Susie's brother and Susie for an example). There is some additional information that you need for these cats. Susie has a pink nose (the dominant condition). Susie's father also has a pink nose. Susie's brother has a gray nose (the recessive condition). Susie and "Susie's 1st partner" had one kitten, and that kitten had a gray nose. Fred has a pink nose. Fred's father has a gray nose. Fred's mother and her parents are all homozygous dominant for pink noses. Q1: Susie's genotype is: nn NN none of these is correct Nn Q2: Susie can produce gametes that are: N or n only n NN or nn only N q3: Fred can produce…Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口n the space below, use colored pencils to create a pedigree with the following information. Follow the guidelines for a pedigree when creating this one. Ray and Elaine were married in 1970. They both had normal vision. They had 2 daughters and then a son. Both daughters, Alicia and Candace, had normal vision and never had any children of their own. The son, Mike, was colorblind. The son married Beth who also had normal vision and they had 2 children of their own, first Greg then Victoria. Victoria was colorblind, but Greg was not. Colorblindness is a sex-linked recessive trait. Do not forget what shapes are male and female. Place the names and genotypes of the people under their shape. Color your individuals the following: Red- for colorblindness White-for regular vision Blue- for individuals with regular vision but are carriers Green- unknown genotype
- A corn geneticist wants to obtain a corn plant that hasthe three dominant phenotypes: anthocyanin (A), longtassels (L), and dwarf plant (D). In her collection ofpure lines, the only lines that bear these alleles are AALL dd and aa ll DD. She also has the fully recessive lineaa ll dd. She decides to intercross the first two and testcross the resulting hybrid to obtain in the progeny aplant of the desired phenotype (which would have to beAa Ll Dd in this case). She knows that the three genesare linked in the order written, that the distance between the A/a and the L/l loci is 16 m.u., and that thedistance between the L/l and the D/d loci is 24 m.u.a. Draw a diagram of the chromosomes of the parents,the hybrid, and the tester.b. Draw a diagram of the crossover(s) necessary toproduce the desired genotype.c. What percentage of the testcross progeny will be ofthe phenotype that she needs?d. What assumptions did you make (if any)?A family tree of sorts is called a pedigree. The symbols used for a pedigree are: female, unaffected female, affected ☐male, unaffected male, affected I 11 III 1 Pedigree Chart Minor Peta #2 Siblings are placed in hirth order from left to right and are labeled with Arabic numerals. Each generation is labeled with a Roman numeral. Therefore, the male exhibiting the trait in the pedigree below in the bottom, center would be identified as III-4. 1. Which members of the family above are affected by Huntington's Disease? 4. How many girls did II-1 and 11-2 have? 3. How many children did individuals 1-1 and 1-2 have? 2. There are no carriers for Huntington's Disease- you either have it or you don't. With this in mind, is Huntington's disease caused by a dominant or recessive trait? 5. How are individuals III-2 and II-4 related? 8 -Huntington's DiseaseEach box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes: What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?
- . A geneticist mapping the genes A, B, C, D, and E makestwo 3-point testcrosses. The first cross of pure lines isA/A ⋅ B/B ⋅ C/C ⋅ D/D ⋅ E/E × a/a ⋅ b/b ⋅ C/C ⋅ d/d ⋅ E/EThe geneticist crosses the F1 with a recessive tester andclassifies the progeny by the gametic contribution ofthe F1:A ⋅ B ⋅ C ⋅ D ⋅ E 316a ⋅ b ⋅ C ⋅ d ⋅ E 314A ⋅ B ⋅ C ⋅ d ⋅ E 31a ⋅ b ⋅ C ⋅ D ⋅ E 39A ⋅ b ⋅ C ⋅ d ⋅ E 130a ⋅ B ⋅ C ⋅ D ⋅ E 140A ⋅ b ⋅ C ⋅ D ⋅ E 17a ⋅ B ⋅ C ⋅ d ⋅ E 131000The second cross of pure lines is A/A • B/B • C/C • D/D •E/E × a/a • B/B • c/c • D/D • e/e.The geneticist crosses the F1 from this cross with arecessive tester and obtainsA ⋅ B ⋅ C ⋅ D ⋅ E 243a ⋅ B ⋅ c ⋅ D ⋅ e 237A ⋅ B ⋅ c ⋅ D ⋅ e 62a ⋅ B ⋅ C ⋅ D ⋅ E 58A ⋅ B ⋅ C ⋅ D ⋅ e 155a ⋅ B ⋅ c ⋅ D ⋅ E 165a ⋅ B ⋅ C ⋅ D ⋅ e 46A ⋅ B ⋅ c ⋅ D ⋅ E 341000The geneticist also knows that genes D and E assortindependently.a. Draw a map of these genes, showing distances inmap units wherever possible.b. Is there any evidence of interference?This pedigree (Pedigree #2) illustrates the inheritance of a simple Mendelian trait. If individuals III- 5 and III-6 have children, what are the chances that the children would have this disorder? 0% 1/4 2/3 O 1/6 ㅇㅁonpin=FIGIH te. G Gmail O YouTube Maps In humans, having dimples is dominant over not having dimples. In the Punnett square below, show a cross between a parent who is homozygous for dimples (DD) with a parent who is heterozygous for dimples (Dd). Then complete the table of genotypes and phenotypes for this cross. Genotypes Phenotypes Tt A Open notes navigator
- We have crossed true-breeding flies today. Wild type to mutant. Their phenotypes were wt and vg se. (Let’s not worry about males and females for now, just assume both genes are autosomal, which is normal in a Mendelian experiment). The results of a cross are phenotypes. I will be asking you for numbers or a ratio of phenotype numbers you expect to see in the offspring from this cross. To answer this, you’ll need to start with the genotypes of parents, then write their gametes, then write the offspring genotypes, then get the phenotypes based on them. Predict the results of this cross: In case both mutations are recessive; In case both mutations are dominant; In case vestigial wings are recessive and the sepia eyes are dominant.I just want an explanation of what is in bold please. Lab Introduction: A dihybrid cross is a cross between individuals that involves two pairs of contrasting traits. To Predict the results of a dihybrid, cross all possible combinations of the four alleles from each parent must be considered. You will examine a dihybrid cross involving both color and texture. Purple (P), is dominate to yellow (p), and smooth texture (S) is dominant to wrinkled (s). Both parent plants are heterozygous for both traits. Review genetics and the use of Punnett squares in a biology text before doing this experiment.MATERIALS: Assume you have ear of Corn. You need a heterozygous X heterozygous 9:3:3:1, purple/yellow, starchy/sweet. PROCEDURE: From above please write out: The crop The parental (P) cross phenotype, genotype, gametes The F1 progeny Genotype and Phenotype Cross between two F1 Selfed testcross The F1 gametes The expected F2 results, genotype, phenotype, genotypic ratio, phenotypic ratio. 1.…n a container/tub, place 50 pieces ofred paper, 50 pieces of pink paper, and50 pieces of white paper. Let usassume that each color is thephenotypic expression of thegenotypes homozygous dominant AA(red), heterozygous Aa (pink), andhomozygous recessive aa (white).Without looking, randomly pick 20 pieces of paper from your container/tub and assumethat those individuals died upon picking, thus will be removed from your population. a. If you are a picky eater and prefer the white only, what do you think will happen in the genotypic frequency and allelic frequencies of the red, pink and white pieces of papers?