Determine the total amount of heat released (in kJ) when 413 g of isopropyl alcohol (C3H3O) are cooled from the gas state at 100. °C to a liquid at -42.0 °C. The normal boiling point of isopropyl alcohol is 82.3 °C. The heat of vaporization at the boiling point is 39.9 kJ/mol. The specific heat capacity of isopropyl alcohol in the vapor state is 1.54 J/g.°C. The specific heat capacity of liquid isopropyl alcohol is 2.68 J/g.°C.

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Chapter6: Thermochemisty
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Problem 6.83QP: The cooling effect of alcohol on the skin is due to its evaporation. Calculate the heat of...
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Determine the total amount of heat released (in kJ) when 413 g of isopropyl alcohol (C3H3O) are cooled from the gas state at 100. °C to a liquid at -42.0 °C.
The normal boiling point of isopropyl alcohol is 82.3 °C.
The heat of vaporization at the boiling point is 39.9 kJ/mol.
The specific heat capacity of isopropyl alcohol in the vapor state is 1.54 J/g.°C.
The specific heat capacity of liquid isopropyl alcohol is 2.68 J/g.°C.
Transcribed Image Text:Determine the total amount of heat released (in kJ) when 413 g of isopropyl alcohol (C3H3O) are cooled from the gas state at 100. °C to a liquid at -42.0 °C. The normal boiling point of isopropyl alcohol is 82.3 °C. The heat of vaporization at the boiling point is 39.9 kJ/mol. The specific heat capacity of isopropyl alcohol in the vapor state is 1.54 J/g.°C. The specific heat capacity of liquid isopropyl alcohol is 2.68 J/g.°C.
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