Determine the source to drain current of the circuit shown below. MyРМOS M1 |l=5u w=20u V1 + Parameter NMOS РMOS R1 K 120 μΑ/V2 40 μΑ/V2 30k Vro 800 mV -900 mV 0.5 Vỹ 0.6 yV 0.7 V 0.6 V O 158.3675 uA O 1.34 mA O 1.34 uA O 324.1629 uA
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- Date 03175996 28) A battery of emif 4V and grternal. xesistance 2n s joined to a desistor of 8 2 calculate the terminal potential difference. What additional xesistance in sedies with 8-2 sesistor Would produce a texminal pd of 3.6V? Taacher's SignalureFAIRCHILD Discrete POWER & Signal Technologies SEMICONDUCTOR ru 1N4001 - 1N4007 Features • Low torward voltage drop. 10 a14 * High aurge eurrent cepablity. 0.160 4.06) DO 41 COLOR BAND DGNOTEs CAT-Cos 1.0 Ampere General Purpose Rectifiers Absolute Maximum Ratings T-26*Cuness atnerwioe rated Symbol Parameter Value Units Average Recttied Current 1.0 375" lead length a TA - 75°C Tsargei Peak Forward Surge Current 8.3 ms single halr-sine-wave Superimposed on rated load JEDEC method) 30 A Pa Total Device Dissipetion 2.5 20 Derste above 25°C Ra Tag Thermal Resistence, Junction to Amblent 5D Storage Temperature Range 55 to +175 -55 to +150 Operating Junetion Temperature PC "These rarings are imithg valuee above whien the serviceatity or any semiconductor device may te impaired. Electrical Characteristics T-20'Cunieas ofherwise roted Parameter Device Units 4001 4002 4003 4004 4005 4006 4007 Peak Repetitive Reverse Vellage Maximum RME votage DC Reverse Voltage Maximum Reverse Current @ rated VR…ier quesuon Will save this response. Quèstion 6 Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to iL-DC =05A RL VLDC =20V 220V omsb 0.01 F 0.02 F 0.0167 F Hows b None of the above DEV Chp
- Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the aboveIn the circuit shown below. Determine the following a. Vs (at the secondary) b. Vout (across RL) c. Vrip (ripple votage) d. VDC e. PIV (Peak Inverse Voltage) 10:1 Output 115 V mis 60 Hz RL 2.2 k) D, 50μF- All diodes are IN4001. Tund AlMannai EENG261 Page 5/11Give the meaning of each acronym of solid state devices. Also sketch the schematic symbol for each device. SUS Shockley diode D-MOSFET JFET SCR DIAC THYRISTOR Device TRIAC 1. 3. 4. 6. 8. 10. 12. 14. Symbol 2. 5. 7. 9. 11. 13. 15. Meaning No entry
- In the circuit shown below. Let Vm=37 V and i,=21 mA and Voa -0.7 V: iD is C0.8 ko 3 ko Vmcos(wt)V For t = Os, the current in the diode equals: Oa. 2 mA Ob. 0 mA Oc. -2 mA Od. 4 mA Ift = T/4, then the current in the diode equals: Оа. 4.24 mA Оb. 3.39 mA Oc. 5.3 mA Od. 2.71 mAPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to c 20:5A L VI-DC20V 220V omsh T 0.01 F 0.02 F 0.0167 F None of the above euerIn the circuit shown below. Let Vm-35 V and i-20 mA and VpQ -0.7 V: iD 3 kQ 0.8 kO Vmcos(@t)V For t Os, the current in the diode equals: Oa. 0 mA Ob. 4 mA Oc. 2 mA Od. 6 mA If t = T/4, then the current in the diode equals: Oa. 6.29 mA Ob. 5.03 mA Oc. 4,03 mA Od. 7.86 mA If t = T/2, then the current in the diode equals: Oa. 15.24 mA Ob. 13.24 mA Oc. 19.24 mA Od. 17.24 mA
- A clamper circuit has 20 Vp-p. 100Hz square wave input voltage. The circuit consists of silicon diode IN4001 and 3V battery as shown in Figure 1 C. 0.1 µF D R Vi(t) 50 k2 Vo(t) 3 V Figure 1 a) Find the output voltage for all input voltages values. b) Sketch the output waveform, Vo(t).Consider the circuit shown in the figure below with R1=16 ko and R=8 klQ. The Zener diode voltage is Vz = 3.5 V, then the currents Iz and lu respectively, are equal to: Ri of ww RL 20 V O a. 0.594 mA, 0.438 mA Ob. 0.394 mA 0.237 mA Oc 0.794 mA, 0.637 mA O d. 0.994 mA, 0.838 mAA 1N4738A zener diode has a ZZ of 4.5 Ω. Taking the data from the datasheet we have VZ = 8.2 V with a test current, IZ, of 31 mA. What is the voltage across the zener terminals when the current is 15 mA? When the current is 55 mA? Make the representation of the values by means of their curve characteristic.