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Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO3 after 80.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 106. 1 3 4 NEXT Use the table below to determine the moles of reactant and product ater the reaction the acid and base. H2NNH2(aq) H*(aq) H,NNH; *(aq) + Before (mol) Change (mol) After (mol)

Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO3 after 80.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 106. 1 3 4 NEXT Use the table below to determine the moles of reactant and product ater the reaction the acid and base. H2NNH2(aq) H*(aq) H,NNH; *(aq) + Before (mol) Change (mol) After (mol)

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.93QE
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Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO3 after 80.0 mL of the strong acid has been added. The value of Kb for H,NNH, is 3.0 × 10-6. K PREV 1 2 4. NEXT > Based on the result of the acid-base reaction, set up the ICE table in order to determine the unknown. H2NNH3*(aq) + H2O(I) H;O*(aq) + H2NNH2(aq) Initial (M) Change (M) Equilibrium (M) 5 RESET +x 0.0333 0.0667 0.100 0.200 0.0667 + x 0.0667 - x 0.0333 + x 0.0333 -x 0.100 - x 0.200 + x 0.200 x 0.100 + x 1L
Transcribed Image Text:Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO3 after 80.0 mL of the strong acid has been added. The value of Kb for H,NNH, is 3.0 × 10-6. K PREV 1 2 4. NEXT > Based on the result of the acid-base reaction, set up the ICE table in order to determine the unknown. H2NNH3*(aq) + H2O(I) H;O*(aq) + H2NNH2(aq) Initial (M) Change (M) Equilibrium (M) 5 RESET +x 0.0333 0.0667 0.100 0.200 0.0667 + x 0.0667 - x 0.0333 + x 0.0333 -x 0.100 - x 0.200 + x 0.200 x 0.100 + x 1L
Question 16 of 20 Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO3 after 80.0 mL of the strong acid has been added. The value of Kb for H,NNH, is 3.0 x 106, 9- 1 4 NEXT > Nse the table below to determine the moles of reactant and product ater the reaction of the acid and base. H2NNH2(aq) H*(aq) H2NNH3*(aq) Before (mol) Change (mol) After (mol) 5 RESET 0.100 + x 0.100 - x 0.100 0.200 +x 0.200 + x 0.200 - ) 1.00 x 103 -1.00 x 10-3 2.00 x 10 3 -2.00 x 10-3 6.00 x 103 -6.00 x 103 7.00 x 103 -7.00 x 103 8.00 x 103 -8.00 x 10 3 ↑
Transcribed Image Text:Question 16 of 20 Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO3 after 80.0 mL of the strong acid has been added. The value of Kb for H,NNH, is 3.0 x 106, 9- 1 4 NEXT > Nse the table below to determine the moles of reactant and product ater the reaction of the acid and base. H2NNH2(aq) H*(aq) H2NNH3*(aq) Before (mol) Change (mol) After (mol) 5 RESET 0.100 + x 0.100 - x 0.100 0.200 +x 0.200 + x 0.200 - ) 1.00 x 103 -1.00 x 10-3 2.00 x 10 3 -2.00 x 10-3 6.00 x 103 -6.00 x 103 7.00 x 103 -7.00 x 103 8.00 x 103 -8.00 x 10 3 ↑
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