Determine the impedance Z, for maximum average power transfer and the value of the maximum average power transferred to Z, for the circuit below. 12/0°V 6/0°V Ht -j1N 320 Z, | 4/0° V ZL = -j6.3 N Pmax = 11.91 W Ob. ZL = 5 N Pmax = 5.28 W C. ZL = 0.66-j6.92 N Pmax = 4.11 W O d. Because the circuit is not symmetric, the maximum average power cannot be delivered to ZĮ. Oe. ZL = j3.06 N ww

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
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Determine the impedance Z, for maximum average power transfer and the value of the maximum average power transferred to Z, for the circuit
below.
12/0°V
6/0°V
Ht
-j1N
320
Z,
| 4/0° V
ZL = -j6.3 N
Pmax = 11.91 W
Ob.
ZL = 5 N
Pmax = 5.28 W
C.
ZL = 0.66-j6.92 N
Pmax = 4.11 W
O d. Because the circuit is not symmetric, the maximum average power cannot be delivered to ZĮ.
О е.
ZL = j3.06 N
Pmax = 13.18 W
ww
Transcribed Image Text:Determine the impedance Z, for maximum average power transfer and the value of the maximum average power transferred to Z, for the circuit below. 12/0°V 6/0°V Ht -j1N 320 Z, | 4/0° V ZL = -j6.3 N Pmax = 11.91 W Ob. ZL = 5 N Pmax = 5.28 W C. ZL = 0.66-j6.92 N Pmax = 4.11 W O d. Because the circuit is not symmetric, the maximum average power cannot be delivered to ZĮ. О е. ZL = j3.06 N Pmax = 13.18 W ww
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