Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface density of atoms for (a)a (100) plane and (b) a (110) plane. (Ans. (a) 8.86 x 104 cm-2, (b) 6.27 x 101" cm-2]

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter9: Liquids, Solids, And Materials
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HW(2 questions)
Determine the distance between nearest (110) planes in a simple cubic lattice with a
lattice constant of an = 4.83 Å. (y 7s
The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface
density of atoms for (a)a (100) plane and (b) a (110) plane.
(Ans. (a) 8.86 x 10+ cm-, (b) 6.27 x 10" cm-2]
Transcribed Image Text:HW(2 questions) Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y 7s The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface density of atoms for (a)a (100) plane and (b) a (110) plane. (Ans. (a) 8.86 x 10+ cm-, (b) 6.27 x 10" cm-2]
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