Determine the Average Mass and the Standard Deviation for the following data: Mass of pennies in grams = 1.5021, 1.4736, 1.4966, 1.5164, 1.5420, 1.4699 g. Average Mass grams +/- Standard Deviation grams
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- In order to find the density of a solution of unknown density, 10 mL of solution was drawn into a clean and dry beaker three times with a pipette and weighed and the weighing results were found to be 65.1452 g, 64.9982 g, 65.1027 g. Calculate the density of the solution and the standard deviation of the measurements, since the empty weight of the beaker is 52.2461 g.A researcher has developed a new analytical method to determine the percent by mass iron in solids. To test the new method, the researcher purchases a standard reference material sample that is 2.85% iron by mass. Analysis of the iron standard returns values of 2.75%, 2.89%, 2.77%, 2.81%, and 2.87%. Are the results of the new method significantly different from the standard reference sample? (Hint: Use Confidence Interval)Find numerical value: Report your answer in proper Sig. Figs. i) (5.6 × 104)+(7.89 x 102). Show Your Working Here: 1.00×105 ii) 8.00 ? Show Your Working Here:
- 15. In preparing a certain ointment, a pharmacist used 28.35 grams of zinc oxide instead of the 31.1 grams called for. Calculate the percentage of error on the basis of the desired quantity.What is the average ratio in this chart? Please show me the calculation too! Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1 0.016 : 0.0015= 32:3 Average RatioSuppose a student measured the mass of a sample that has a known mass of 40.5809 g using an analytical balance. The mass they observed was unstable, constantly jumping between 39.5 and 41.5. Choose all of the following reasons that could cause this error. O The doors to the analytical balance were not closed completely, allowing an air current to circulate inside the balance. One weigh boat was used to tare the balance while a different one was used when the sample was massed. Twice the amount of sample was placed on the analytical balance. O The sample was heated, causing a convective flow.
- 3. From the following data, compute the percent recovery of copper. If the masses given are correct (no weighing errors), give a possible explanation for the fact that the percent recovery is greater than 100%. Initial mass of copper Mass of recovered copper + dish Mass of evaporating dish Mass of recovered copper Percent Recovery 1.0531 g 180.9020 g 179.8463 g %A student performed an analysis of a sample for its calcium content andgot the following results: 14.92% 14.91% 14.88% 14.91%The actual amount of calcium in the .sample is 15.70%. What conclusions can you draw about the accuracy and precision of these results?7. 22 This question is about several salts. (a) A hydrated salt, compound A, is analysed and has the following percentage composition by mass: Cr, 19.51%; CI, 39.96%; H, 4.51%; O, 36.02%. Calculate the formula of compound A, showing clearly the water of crystallisation. Show your working. formula of compound A = (b) A student carries out an experiment to determine the amount of water of crystallisation in the formula of another hydrated salt. The student intends to remove the water by heating the hydrated salt. A diagram of the apparatus used by the student is shown below. crucible pipeclay triangie The student adds the hydrated salt to the crucible and weighs the crucible and contents. The student heats the crucible and contents and allows them to cool. The student weighs the crucible and residue. The student's results are shown below. 16,84 Mass of crucible + hydrated salt/g 16.26 Mass of crucible + residue after heating/g
- What are replicates in Analytical Chemistry? O The component of a sample that repeats over different assays. Similar assays done to different samples A sample that contains exactly the same amount of analytes than the original sample similar samples that are analyzed at the same time and in the same wayA compound contains only Mn and F. The ratio of Mn and F is 1.73 moles of F per 1 mole of Mn. If the empirical formula is expressed as MnFx, what is the numerical value for x? If the formula is MnF5, you would enter the number 5. Please enter a whole number (i.e. round the number to the nearest whole number) and DO NOT include any units.The mass of earth's atmosphere is 5.3x1015 metric tons. The atmospheric abundance of helium is 0.7ppm when expressed as a fraction by mass instead of by volume .How many metric tons of helium are there in the atmosphere. How may moles of Helium is this