Determine (a) the x2 test statistic, (b) the degrees of freedom, (c) the critical value using x = 0.05, and (d) test the hypothesis at the x = 0.05 level of significance. HOPA PB PC Po 1 H₁: At least one of the proportions is different from the others. (a) The test statistic is (Type an exact answer.) Outcome Observed A B C DO 37 37 43 43 Expected 40 40 40 40 40
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- A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, µ, of the population from which the sample was drawn. Use the critical-value approach. x= 137, s = 14.2, n= 20, Ho: u= 132, Ha: u 132, a= 0.1A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, µ, of the population from which the sample was drawn. Use the critical-value approach. Sample mean = 7.1 S = 2.3 n = 18 a = 0.01 Ho: µ = 10 %3D H1: μ< 10 1. The test statistics is (Round to three decimal places) 2. The critical value(s) is/are (If there are two critical values separate each with a comma.) 3. The decision is to the null hypothesis. (Enter R if you reject and enter F if you fail to reject) ASUS VivoBookA sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, p, of the population from which the sample was drawn. Use the critical-value approach. x= 24.4, s = 9.2, n = 25, Ho: µ= 26, H,: µ < 26, a = 0.05 O A. Test statistic: t= - 0.87. Critical value: t= - 1.708. Do not reject H,. There is not sufficient evidence to conclude that the mean is less than 26. O B. Test statistic: t= - 4.35. Critical value: t= - 1.711. Reject Hp. There is sufficient evidence to conclude that the mean is less than 26. OC. Test statistic: t= - 4.35. Critical value: t= - 1.708. Reject Hn. There is sufficient evidence to conclude that the mean is less than 26. O D. Test statistic: t= - 0.87. Critical value: t= - 1.711. Do not reject Hn. There is not sufficient evidence to conclude that the mean is less than 26.
- A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, µ, of the population from which the sample was drawn. Use the critical- value approach. Sample mean = 7.5 S = 1.8 n = 18 a = 0.01 %3D Họ: µ = 10 H1: µ <10 1. The test statistics is (Round to three decimal places) 2. The critical value(s) is/are (If there are two critical values separate each with a comma.) 3. The decision is to the null hypothesis. (Enter R if you reject and enter Fif you fail to reject)Use the sample of the greenhouse gas emissions of 32 different cars. (The amounts are in tons per year, expressed as CO2 equivalents.) Use a 0.05 significance level to test the claim that all cars have a mean greenhouse gas emission of 8.00 tons. Find the statistic, p-value and the critical value (or values). (I can ask for the satistic ,p value and critical value separately if needed) Data: Car GHG Acura RL 8.7 Acura TSX 7.2 Audi A6 7.7 BMW 525i 7.7 Buick LaCrosse 7.9 Cadillac STS 8.7 Chevrolet Impala 8.2 Chevrolet Malibu 6.8 Chrysler 300 9.3 Dodge Charger 9.3 Dodge Stratus 7.4 Ford Crown Victoria 9.3 Ford Focus 6.5 Honda Accord 6.6 Hyundai Elantra 6.7 Infiniti M35 9 Jaguar XJ8 8.6 Kia Amanti 9.3 Kia Spectra 6.5 Lexus GS300 7.4 Lexus LS 8.7 Lincoln Town Car 9.3 Mazda 3 6.5 Mercedes-Benz E 7 Mercury Grand Marquis 9.3 Nissan Altima 7.1 Pontiac G6 7.2 Saturn Ion 6.7 Toyota Avalon 7.2 Toyota Corolla 5.5 Volkswagon Passat…A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, µ, of the population from which the sample was drawn. Use the critical-value approach. x= 24.4, s = 9.2, n= 25, Ho: H = 26, Hạ:µ < 26, a = 0.05 %3D . .. O A. Test statistic: t= - 4.35. Critical value: t= - 1.708. Reject Ho. There is sufficient evidence to conclude that the mean is less than 26. O B. Test statistic: t= - 4.35. Critical value: t= - 1.711. Reject Ho. There is sufficient evidence to conclude that the mean is less than 26. O c. Test statistic: t= - 0.87. Critical value: t= - 1.708. Do not reject Ho. There is not sufficient evidence to conclude that the mean is less than 26. O D. Test statistic: t= - 0.87. Critical value: t= - 1.711. Do not reject Ho. There is not sufficient evidence to conclude that the mean is less than 26.
- A survey is conducted to determine if there is a difference in the proportion of students, parents, and The conditions for inference are met. The chi-square test statistic is 0.19 and df = 2. What is the appropriate decision using a = 0.05? teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the table. Find the chi-square table here. Because the P-value is less than a = 0.05, the null hypothesis should be rejected. Student Parent Teacher Because the P-value is less than a = 0.05, the null hypothesis should not be rejected. Yes 24 12 Volunteer? No 21 13 Because the P-value is greater than a = 0.05, the null hypothesis should be rejected. The researcher would like to test these hypotheses: Because the P-value is greater than a = 0.05, the null hypothesis should not be rejected. Họ: There is no difference in the distribution of responses among these three…A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, H, of the population from which the sample was drawn. Use the critical- value approach. Sample mean = 7.8 S = 1.5 n = 18 a = 0.01 Ho: µ = 10 H1: µ < 10 1. The test statistics is (Round to three decimal places) 2. The critical value(s) is/are (If there are two critical values separate each with a comma.) 3. The decision is to the null hypothesis. (Enter R if you reject and enter F if you fail to reject)After running a regression you conduct a hypothesis test of Ho: ß = 2.5 versus Hạ: B + 2.5 is performed using a = 0.10. The value of the test statistic z = -1.80 (the critical value is -1.645). If the true value of B is 2.5, does the conclusion you reach result in Type I, Type II error, or the correct decision? O Type II Error O Type I Error O correct decision not enough information
- Use the t-distribution table to find the critical value(s) for the indicated alternative hypotheses, level of significance a, and sample sizes n, and n,. Assume that the samples are independent, normal, and random. Answer parts (a) and (b). Ha: H1 > H2, a= 0.025, n, = 13, n2 = 11 (a) Find the critical value(s) assuming that the population variances are equal. 2.074 (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) (b) Find the critical value(s) assuming that the population variances are not equal. (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.)A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, µ, of the population from which the sample was drawn. Use the critical-value approach. Sample mean 3.12 S = 0.59 n = 9 a = 0.01 Ho: µ = 2.85 H1: µ > 2.85 1. The test statistics is (Round to three decimal places) 2. The critical value(s) is/are (If there are two critical values separate each with a comma.) 3. The decision is to the null hypothesis. (Enter R if you reject and enter F if you fail to reject) ASUS VivoBook ロ/点 f9 home f10 end doBa 7. 8. 9. 3.For the given data, (a) find the test statistic, (b) find the standardized test statistic, (c) decide whether the standardized test statistic is in the rejection region, and (d) decide whether you should reject or fail to reject the null hypothesis. The samples are random and independent. Claim: µ1 <µ2, a = 0.01. Sample statistics: x, = 1225, n, = 40, x2 = 1195, and n2 = 60. Population statistics: o, = 65 and o2 = 120. (a) The test statistic for u, - 42 is (b) The standardized test statistic for H - 42 is 1.61 (Round to two decimal places as needed.) (c) Is the standardized test statistic in the rejection region? O Yes O No (d) Should you reject or fail to reject the null hypothesis? Ho:HyZH2; Hgi HqSEE MORE QUESTIONS
