Determination of vertical displacement of Mid-Term Project pipe assembly Find the vertical displacement at position C in the figure. Pipe inner diameter: 40 mm, Pipe outer diameter: 60 mm 800 mm Material: A-36 Steel 600 N -By the force 600N, the AB part of the pipe is subjected to bending and torsional loads. BC part is subjected to bending load. -The energy equation by this load is as follows. Energy equation by torsional load: 400 mm T°dx (U), = : 2GJ Problem: Energy equation by bending load a) First, draw a free body diagram and the AB part Of the bending /torsional load of the BC and Derive the bending load equation. So By applying it to the high energy formula, Save energy and make it the same as external energy Release to find the vertical displacement. b) Creo modeling and structural analysis M²dx (U), 2EI -The sum of the internal energy of 2 energy is as follows. U=U: +Ub -Due to energy conservation, the sum of the internal energy U is the external due to the load 600 NGet the vertical displacement at position C It is equal to the magnitude of negative energy. U= (½)PA = (%½)(600)A -> -Vertical displacement A =U /300 Compare it with the value obtained in a).

Determination of vertical displacement of Mid-Term Project pipe assembly Find the vertical displacement at position C in the figure. Pipe inner diameter: 40 mm, Pipe outer diameter: 60 mm 800 mm Material: A-36 Steel 600 N -By the force 600N, the AB part of the pipe is subjected to bending and torsional loads. BC part is subjected to bending load. -The energy equation by this load is as follows. Energy equation by torsional load: 400 mm T°dx (U), = : 2GJ Problem: Energy equation by bending load a) First, draw a free body diagram and the AB part Of the bending /torsional load of the BC and Derive the bending load equation. So By applying it to the high energy formula, Save energy and make it the same as external energy Release to find the vertical displacement. b) Creo modeling and structural analysis M²dx (U), 2EI -The sum of the internal energy of 2 energy is as follows. U=U: +Ub -Due to energy conservation, the sum of the internal energy U is the external due to the load 600 NGet the vertical displacement at position C It is equal to the magnitude of negative energy. U= (½)PA = (%½)(600)A -> -Vertical displacement A =U /300 Compare it with the value obtained in a).

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.5.11P: The hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in...

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