No.Date.Determination of Discharge Thru a SiphonVol.Q=AVt JP1P2+21=(√2) ²29+ 1² + Z2rYtrial #2trial #3t = 75t= 5sY = 340mlV: 250mLthe table below I show calculation please)1TheoreticalActual+Discharge(s)+Discharge(LIS)Formula: Q=(V1)229h = 63.5cmtrial #1t= 10sV = 490 mLcompletetrial+time(s) Volume(ml)1%0+ Difference

Given Distance = 83.5 cm = 0.835 m To find Trials Theoretical discharge Actual discharge Difference…

Answered: Determination of Discharge Thru a…

Engineering

Mechanical Engineering

Determination of Discharge Thru a Siphon Vol

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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formula: Q. (V1)2 29 h = 63.5cm trial #1 490mL trial No. Date Determination of Discharge Thru a Siphon Vol ● Q=AV t ) P1 V2)2 P2 +71 +2 r Y 29 trial #2 trial #3 += 75 t= 5s Y = 340ml V: 250mL the table below. I show calculation please) 1 Theoretical Actual Discharge Discharge (LIS) (L/₁) t = 10s V = complete + + 1 time(s) Volume / H (m) (mL) + + % Difference
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