Design a CMOS gate circuit for the Boolean expression (circuits and input- output curves) F= XZ + XY W (where W, X, Y and Z are inputs)
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Design a CMOS gate circuit for the Boolean expression (circuits and inputoutput curves) on Pspice
F= XZ+ XYW
(where W, X, Y and Z are inputs)
Step by step
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- - The proportional distribution of A, B, C, D signals is given in the table as a percentage. It “logic 1” when the signals are accepted as active, “logic 0” when they are accepted as passive. takes. - When the proportional sum of active signals is over 50%, its output is "logic1", When we accept "logic 0" when it is below 50%, the output in the table Find the values. - Create an X function based on the logic values you find. Simplify the created X function. - Design the simplified function with NAND and NOR gates. - Set up the circuits you designed with NAND and NOR gates and observe the outputs. Show the output values by drawing a table, applying all possibilities to the input values.- The proportional distribution of A, B, C, D signals is given in the table as a percentage. It “logic 1” when the signals are accepted as active, “logic 0” when they are accepted as passive. takes. - When the proportional sum of active signals is over 50%, its output is "logic1", When we accept "logic 0" when it is below 50%, the output in the table Find the values. - Create an X function based on the logic values you find. Simplify the created X function. - Design the simplified function with NAND and NOR gates.subject name is "DIGITAL ELECTRONICS" 1: A) What will be the hexadecimal equivalent of the octal number 375525.3276? B) The smallest and largest numbers that can be represented in 13-bit 2's compliment. c) consider a 4-input XOR gate with inputs A, B, C and D. What will happen if the input A is permanently connected to 0. Justify your statement also.
- (b) For a two-input OR gate, Find the standard SOP and POS expressions as a function of input variables.Which of the following is correct regarding the comparison between TTL and CMOS? >CMOS design is less complicated as compared to TTL. >CMOS circuits consume more power compared to TTL circuits at rest. >CMOS allows in a single chip a much higher density of logic functions compared to TTL. >CMOS chips are a lot more susceptible to static discharge compared to TTL chips.EXERCISES 1. Construct various basic logic gates with CMOS NAND gate. 2. If one of the two inputs of a NAND gate is connected to "1", it will act as a NOT gate. What happens if one input is connected to "0"? MULTIPLE CHOICE QUESTIONS () 1. The output F of a NAND gate is equal to: 1. A+B 2. AB 3. A+B ( ) 2. Which of the followings can be used to construct a NOT gate? ( )3. is equivalent to which of the followings? 2-11
- Write an 8086 assembly language a program to find the number of (1) in the AX and add it to the BL and the number of () in the AX and add it to the BH ? Note: Answer in Hexadecimal .Suppose, a "word-wide" input device (i.e. each input is 2 bytes in size) is connected to the port of an 8086 microprocessor located at address FAh. Additionally, two "byte-wide" output devices (i.e. each output data is 1 byte in size) are connected to the ports located at the address FA8AH and 5C3Bh. Now, write an assembly code snippet that does the following- a. Read a word from the input device. b. Split the word into two bytes. c. Write the high byte to the port address FA8AH and the low byte to the port address 5C3BH.Construct a circuit diagram that checks whether the two numbers A and B are in the ratio of 2:3. Also, derive the final Boolean equation for the function. F = 1 if A: B = 2: 3,0 otherwise Here, A and B both are 3 bit binary numbers. NB: You cannot use the IC of comparator, meaning for the comparison part, you need to draw the gate level diagram. You can use block level diagrams for the rest of the parts.
- Q1: Design and implement an asynchronous counter that counts from 0000 up to 1100 (modulus 13). Use OR gate, and show in the drawing how the OR gate is connected to truncate the state 1101.Use Verilog to design an FSM. The FSM accepts an input binary sequence such as 001010011101.... Its output is zero except when the number of 1's that have been input is a multiple of three. In the example below, the output that is observed after each input bit is received is shown directly below the input bit received: input : 0 1 0 0 1 1 0 0 1 0 1 0 0 1 0 1 0 1 1 0 1 1 0 1 1 0 1 1 output: 1 1 0 0 0 0 1 1 1 0 0 0 0 0 1 1 0 0 0 1 1 0 0 0 1 0 0 0 1 Note: Before any bits have been received, the output is 1. This is because zero 1's is also a multiple of three. Materials to be submitted: 1. Verilog codes for FSM module. You can choose either two-always or three-always blocks style. 2. Verilog codes for testbench using the above example 3. Image of the screen that shows the test results.Problem #1: 7-4. A binary ripple counter starts from 0 and counts up to 511. (a) What is the MOD number of this counter? (b) How many J-K FFs will be required to design this counter? (c) Find the value of the FFs after 520 input pulses. (d) If the input signal has a frequency of 1024 kHz, what will the fre- quency at the MSB output?