Define the time complexity of this ABC algorithm in Big-O notation
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3. Define the time complexity of this ABC
![procedure ABC (input/output S : TabInt, inputN : integer)
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i : integer
: integer
Temp : integer
Pass
ALGORITMA
if N > 1 then
Pass traversal [2..N]
Temp + Sрass
i E Pass-1
while (Temp < Si) and (i > 1) do
Si+1 € Si
i e i - 1
if (Temp >= Si) then
Si+1 E Temp
else
Si+1 E Si
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- 497 Bytes Write a recursive function that returns the sum of the digits of a given integer.Input format :Integer NOutput format :Sum of digits of NConstraints :0 <= N <= 10^9Sample Input 1 :12345Sample Output 1 :15Sample Input 2 :9Sample Output 2 :9 Solution:///////////// public class solution { public static int sumOfDigits(int input){ int sum; if(input<10){ return input; } sum = (input % 10) + sumOfDigits(input / 10); return sum; }}. .Answer in JavaScript Tim while preparing for his CAT exam, was studying the topic Number Systems. He encountered a loving da question: Given a number N, find the number of pairs (cy) where both x and y are less than N and Highent Common Factor(HCF) of x and y is 1. You have to solve the question for him. Note: 0 can be included within the pairs Input Specification: Input: The number N from which the pairs (x,y) should be obtained Output Specification: Return the total number of pairs Example 1: input1: 4 Output: 9 Explanation: The pairs can be (1,0) ,(0,1) (1,1) (1,2) (2,1) (0, 3) (3,1) (2,3) (0,2) So, a total of 9 pairsCode the function multiplier(). /***** *** //The multiplier function takes 2 integer // parameters n1 and n2 and displays the result // of n1 times n2 //*** *******
- 2.a Σ : {c,A,G,T}, L = { w : w = CAG™T™C, m = j + n }. For example, CAGTTC E L; CTAGTC ¢ L because the symbols are not in the order specified by the characteristic function; CAGTT ¢ L because it does not end with c; and CAGGTTC € L because the number of T's do not equal the number of A's plus the number of G's. Prove that L¢ RLs using the RL pumping theorem.Complete the following function using pass-by-reference: void findMax(int &max, int a) which assigns value ‘a’ to ‘max’ if a > max. Write a pseudo-code then implement a program in C language to find the maximum in a sequence of numbers using this function.c++: How do I set a boolean hasDigit to true if string userInput contains a digit? bool hasDigit;string userInput; hasDigit = false;cin >> userInput; if((isdigit(passCode))) //***{hasDigit = true; } //error***: no matching function for call to ‘isdigit(std::string&)’
- CodeW X bFor fun X C Solved x b Answer + x https://codeworko... CodeWorkout X265: Recursion Programmlng Exercise: GCD The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD , write the missing base case condition and action. This function will compute the greatest common divisor of x and y.You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows: = x and GCD(x, y) = GCD(y, x % y). Examples: GCD (6, 4) -> 2 Your An swer: 1 public int GCD(int x, int y) { if > { 2. > 3. } else { 4. return GCD(y, x % y); 9. { 7. 1:09 AM 50°F Clear 1V 1. 12/4/2021 甲#include<bits/stdc++.h> #include <cstdio> using namespace std; // A function for genrating random number between range [N,M) double rand_gen(double M, double N) { return M + (rand() / ( RAND_MAX / (N-M) ) ) ; } int main() { cout<<"Enter the radius of circle => "; double r; cin>>r; cout<<"\nEnter the number of points => "; int n; cin>>n; int inside_cn=0; // count of inside points for(int i=1;i<=n;i++) { double x,y; x=rand_gen(0,2*r+1); y=rand_gen(0,2*r+1); double dist_left,dist_right; dist_left=x*x+(y-r)*(y-r); // distance^2 from left semicircle dist_right=(x-2*r)*(x-2*r)+(y-r)*(y-r); // distance^2 from right semicircle if(dist_left<=r*r || dist_right<=r*r) // checking inside condition { cout << fixed;// setting precision for flaoting numbers cout<<"Point No. "<<i<<" (x=…Part (a) Write a python function that computes the binomial coefficient ("). The function should return the correct answer for any positive integer n and k where k=m pass Part (c) Suppose that the number of people in the trial is 100. Then: • Plot a curve that shows how the probability of type 1 error changes with the choice of m, for m = 1,...n assuming that the null hypothesis holds (in red), • On the same picture, plot the probability of type 2 error vs the value of m in the case in which the new drug is effective with proability 0.68 (in blue). You can plot the two curves using matplotlib.pyplot. You can select the color by passing color='r' or color='b' to the plt.plot() function. [4]: n - 100 # your code here def plot_curve (): pass [5]: plot_curve() Part (d) Based on the picture above, what value of m do you think would be suitable to keep both type 1 and type 2 error small at the same time? (You may assume that the company claims the new drug has 68% accuracy) [6]: # your…
- // add.ll define void @add(i32* %ptr1, i32* %ptr2, i32* %val) {ret void} Fill add.ll function to do the following operation: void add(int *ptr1, int *ptr2, int *val) { *ptr1 += *val; *ptr2 += *val; } This is the full question. It is related to LLVM. If it's going to help there is one more code given which is: #include <stdio.h> void add(int *ptr1, int *ptr2, int *val); int main(int argc, char **argv) {FILE *f = fopen(argv[1], "r");int a, b, c;fscanf(f, "%d %d %d", &a, &b, &c);add(&a, &b, &c);printf("%d %d\n", a, b);fclose(f); return 0;}code this:int f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?
