def Trap(f,x): n = len(x)-1; s = 0; for i in range (n): f2 = f(x[i+1]); f1=f(x[i]); s = s + (x[i+1]-x[i]) * ( f1+ f2 )/2 #print(s) %3D %3D return s
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Given code. my main concern is where to place the given variables for the solution. please use code attached
![def Trap(f,x):
n = len(x)-1; s = 0;
for i in range (n):
f2 = f(x[i+1]); f1=f(x[i]);
s = 5 + (x[i+1]-x[i]) * ( f1+ f2 )/2
#print(s)
return s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa437b1f1-94c0-462c-9640-81b3f97959f1%2Fe3bc118c-b650-4886-8bda-c9a0b32373b2%2Fkrk2gow_processed.png&w=3840&q=75)
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- sum = 0; for (int i = 1; i< n; i = sum++ || 2*i)int n = 1; int k - 2; int r = n; if (k < n) { r - kvoid deleteRange( int from, int to) { int i, j = 0; for (i = 0; i < counter; i++) { if (i <= from - 1 || i >= to + 1) { A[j] = A[i]; j++; } } for (int i = 0; i < j; i++) cout << A[i] << " "; } Above method deletes range of elements from an array. Please explain the logic of above code in simple english (algorithm and comments).
- void deleteRange( int from, int to) {int i, j = 0;for (i = 0; i < counter; i++) {if (i <= from - 1 || i >= to + 1) {A[j] = A[i];j++;}}for (int i = 0; i < j; i++)cout << A[i] << " ";} Above method deletes range of elements from an array. Consider array A[] globally declared and counter is its size. Please explain the logic of above code in simple english (algorithm and comments).void radixSort(int arr[], int n) { intm=getMax(arr, n); for (intexp=1; m/exp>0; exp*=10) countSort(arr, n, exp); } void printData(int arr[], int start, int len) { if( start>=len ) return( 0 ); printf("%d\n", arr[start]); printData(arr, start+1, len); } int main() { intarr[]= {8, 9, 3, 4, 7, 2, 5, 6, 1}; intn=sizeof(arr) /sizeof(arr[0]); radixSort(arr, n); printData(arr, 0, n); return0; } In MIPSusing namespace std; int main() int i, m=0,n=4; float arr[100] (55,66,88,1); for(i=0; ib) int [] num = new int [6]; for (int i = 1; i 2) { num [i] = 2 * num[i]-num[i-1]; System.out.println( "num [" + i + ") =" + num [i]);int binsearch (int X , int V [] , int n ) { int low , high , mid , i ; low = 0; high = n - 1; for ( i = 0; i < high ; i ++) { if( V[ i ] > V [ i +1]) return -2; } while ( low <= high ) { mid = ( low + high )/2; if ( X < V [ mid ]) high = mid - 1; else if ( X > V [ mid ]) low = mid + 1; else return mid ; } return -1; } This code takes as input a sorted array V of size n, and an integer X, if X exists in the array it will return the index of X, else it will return -1. 1. Draw a CFG for binsearch(). 2. From the CFG, identify a set of entry–exit paths to satisfy the complete statement coverage criterion. 3. Identify additional paths, if necessary, to satisfy the complete branch coverage criterion. 4. For each path identified above, derive their path predicate…A/ find code optimization method to this code and then find type to this code 1- For(i=1;iRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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