PLEASE DO Q4 IN PYTHON def integrand(x, params):value = 0for coefficient, power in params:value += coefficient *x** powerreturn valuedef trapezoidal_rule(f, a, b, n):x = np.linspace (a, b, n+1) # a- Lower Limit, b-upper limit, n= number of trapezoidfx = f(x)weights=np.ones(n+1)weights[0] /= 2weights [-1] /= 2h (b a) n=integral h✶ np.sum(weightsreturn integral*fx)def plot_errors (x_values, y_values, labels, linestyles, title):plt.figure(figsize=(10, 6))for x, y, label, linestyle in zip(x_values, y_values, labels, linestyles):plt.loglog(x, y, linestyle, label-label)plt.xlabel('Number of Trapezoids (log scale)')plt.ylabel('Error (log scale)')plt.title(title)plt.legend()plt.show()def calculate_slope (x_values, y_values):coefficients = np. polyfit (np.log(x_values), np.log(y_values), 1)return coefficients[0] 4. Use Richardson extrapolation for the trapezoid rule to compute the integral for 15 ✓edx. Compute the 1st, 2nd, 3rd, 4th, and 5th bestapproximation. This is analagous to finding 121, 122, 123, 124, and 125. Once again, make use of the functions that you defined in 1.There is no graph for this exercise--just output the 5 numbers.

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Answered: def integrand(x, params): value = 0 for…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def strPattern(mystr):lenght = len(mystr)mystr1 = ""for i in range(lenght - 1):mystr1 = mystr1 + mystr[i].upper() + str(i + 1)if lenght == 0:return mystr1return mystr1 + mystr[-1].upper()s = input("enter a word: ")print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line HOW CAN I FIX THIS QUESTION?
inhinclude Rsing namespace std; int maxResult( ) int maxVal for (int i { for (int j = 0; j <= n 0; i <= n; i += a) i; j += b) %3D %3D float z = (float)(n (i + j)) / (float)(c); if (floor(z) { int x = int y ceil(z)) i / a; j/ b; maxVal = max(maxVal, x + y (int)z); return maxVal; } int main() { max cout << maxResult( ); return 0; 1 } Input Compilation failed due to fellowing ons main.cpp:7:23: error: 'n' was not declared in this scope 7| for (int i = 0; i <= n; i a) main.cpp:7:31: error: 'a was not declared in this scope for (int i = 0; i <= n; i t= a) %3D main.cpp:9:36: error: b' was not declared in this scope | 6 for (int j = 0; j <= n - i; j - b) %3D main.cpp:11:45: error: 'c was not declared in this scope
A/ find code optimization method to this code and then find type to this code 1- For(i=1;i
a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?
sum = 0; for (int i = 1; i< n; i = sum++ || 2*i)
Deliverable #2: How many operations in nested for loops? Implement the following psuedocode as the function two_dimensional_loop (n) in the cell below: count = 0 for i = 0 to n-1 : for j = i to n-1 : count = count + 1 return count ► def two_dimensional_loop(n) : # complete to satisfy the instructions and implement the pseudocode || return 0 expectEqual (two_dimensional_loop (520),135460) expectEqual (two_dimensional_loop (1234), int(1234* (1234+1)/2)) 个 ↓
Rooks on a rampage def safe_squares_rooks(n, rooks): A generalized n-by-n chessboard has been invaded by a parliament of rooks, each rook represented as a two-tuple (row, column) of the row and the column of the square that the rook is in. Since we are again computer programmers instead of chess players and other normal folks, our rows and columns are numbered from 0 to n - 1. A chess rook covers all squares that are in the same row or in the same column. Given the board size n and the list of rooks on that board, count the number of empty squares that are safe, that is, are not covered by any rook. To achieve this in reasonable time and memory, you should count separately how many rows and columns on the board are safe from any rook. Because permuting the rows and columns does not change the answer to this question, you can imagine all these safe rows and columns to have been permuted to form an empty rectangle at the top left corner of the board. The area of that safe rectangle is…
Given the following pseudocode: function fun2(n) { var outer_count = 0; var inner_count %3D for (i=0; i 0, as an expression of normal arithmetic and n, what is the value of outer_count that counts the number of times the outer loop executes? Enter an expression Fun.2.inner: Assuming n E N and n > 0, as an expression of normal arithmetic and n, what is the value of inner_count that counts the number of times the inner loop executes? Enter an expression
the code: class HighArray { private long[] a; private int nElems; public HighArray(int max) { a = new long[max]; nElems = 0; } public void insert(long value) { a[nElems] = value; nElems++; } public boolean find(long searchKey) { int j; for (j = 0; j < nElems; j++) if (a[j] == searchKey) break; if (j == nElems) return false; else return true; } public long getMax() { if (nElems == 0) return 01; else { long max = a[0]; for (int i = 1; i < nElems; i++) { if (a[i] > max) max = a[i]; } return max; } } public boolean delete(long value) { int j; for (j = 0; j < nElems; j++) if (value == a[j]) break; if (j == nElems) return false; else { for (int k = j; k < nElems; k++) a[k] = a[k + 1]; nElems--; return true; } } public void display() { for (int j = 0; j < nElems; j++) System.out.print(a[j] + " "); System.out.println(""); }} public class HighArrayApp { public static void main(String[] args) { int maxSize =…
void deleteRange( int from, int to) {int i, j = 0;for (i = 0; i < counter; i++) {if (i <= from - 1 || i >= to + 1) {A[j] = A[i];j++;}}for (int i = 0; i < j; i++)cout << A[i] << " ";} Above method deletes range of elements from an array. Consider array A[] globally declared and counter is its size. Please explain the logic of above code in simple english (algorithm and comments).
Maze Runner Function - Implementation of this function is done in a1_partd.py We describe a maze as having row x col cells. For example if row was 3, and col was 4, then we would have a grid of cells as follows. We describe a wall by the two cell numbers the wall separates. If every single wall existed, there would be (row-1)(col) + (col-1)(row) walls. 0 | 1 | 2 | 3 4 | 5 | 6 | 7 8 | 9 | 10 | 11 A Maze class (which you do not need to implement) describes a maze as mentioned above. This class is defined in maze.py. It has methods that you can use to travel through the maze (i.e. figure out where you are, find a neighbour cell etc.) use a recursive maze runner function: def find_path(maze, from_cell, to_cell); The find_path function will find a path from cell number from_cell to cell number to_cell and will return it as a list containing all the cell numbers along the path, from the from_cell to the to_cell. You are allowed to use this function as a wrapper to a recursive function that…
int n = 1; int k - 2; int r = n; if (k < n) { r - k

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