def increment(x):return x + 1def decrement(x):return x - 1def double(x):return x * 2def apply_n(f, x, n):"""Apply function f to x n times.>>> apply_n (increment, 2, 10)125, 8)apply_n(decrement,>>> apply_n(double, 7, 3)56>>>-3"*** YOUR CODE HERE ***" def square(x):return x * Xdef halve(x):return x // 2def twice(f,x):"""Apply f to the result of applying f to x>>> twice (square,3)81>>> twice (square, 4)256>>> twice (halve, 32)8>>> twice (halve, 80)20*** YOUR CODE HERE ***"

The approach is to check the value of variable f. Use if cases to check the value of f and then…

def increment(x): return x + 1 def decrement(x): return x - 1 def double(x): return x * 2 def apply_n (f, x, n): """Apply function f to x n times. >>>apply_n (increment, 2, 10) >>>apply_n (decrement, 5, 8) >>>apply_n(double, 7, 3) 12 -3 56 " YOUR CODE HERE ***

def increment(x): return x + 1 def decrement(x): return x - 1 def double(x): return x * 2 def apply_n (f, x, n): """Apply function f to x n times. >>>apply_n (increment, 2, 10) >>>apply_n (decrement, 5, 8) >>>apply_n(double, 7, 3) 12 -3 56 " YOUR CODE HERE ***

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *p
3: The code on the right is supposed to be the ARM code for procA; however, there are problems with the ARM code. C code: int procA(int x, int y) { int perimeter = (x + y) * 2; I return perimeter; } ARM code: I procA: add rø, r1, r2 mov r1, rø lsl #1 bx lr push {lr} Give the corrected version of the ARM code for procA:
int X[10]={2,0,6,11,4,5,9,11,-2,-1); From the code above, what is the value of X[8] ?
C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".
#include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }
Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
def square(x): return x * X def halve(x): return x // 2 def twice(f,x): """Apply f to the result of applying f to x >>> twice (square,3) 81 >>> twice (square, 4) 256 >>> twice (halve, 32) 8 >>> twice (halve, 80) 20 *** YOUR CODE HERE ***"
-0 FAMAS oro ag -0 1 void printVerticalGraph(int nUnits) { 2 4 9 10 11 12 13 14 15 16 17 456 BARHEIDEN 18 19 20 21 22 23 24 25 26 27 int nRev; printf("%d\n", nUnits); while (nUnits>0){ nRev = getReverse (nUnits); // 1) Adjust nUnits ?? [Q1] ?? while (nRev>0){ nUnits *= 10; // 2) Condition to print * if(?? [Q2]??) { printf("*"); } // 3) Update for nUnits for * case ?? [Q3] ?? }else{ printf(" "); // 4) Update for nUnits for ?? [Q4]?? } // 5) Update to nRev ?? [Q5]?? printf("\n"); case
def sind_approx(x: float) -> float: """ sind_approx(x) returns the Bhaskara I's sine approximation for sine in degrees. This approximation is only valid within the range [0, 180]. The sine approximation is given as: 4 * x * (180 - x) / (40500 - x * (180 - x)) example: sind_approx(90.0) -> 1.0 example: sind_approx(0.0) -> 0.0 example: sind_approx(180.0) -> 0.0 example: sind_approx(45.0) -> 0.7058823529... TODO: add param and return descriptions here """ pass # TODO: replace 'pass' with the function implementation
double tab1[5] = {2,3,4,5,6}; double tab2[5] = {6,5,4,3,2}; for(int i = 0;i<5;i++) { tab1[i] = tab1[i]*tab2[i]; cout<<tab1[i]<<" "; } 12 15 16 15 16 15 15 16 15 12 12 15 16 15 12 12 15 12 15 12
WRITE A CODE IN C++ You work for an analytics organization have been tasked with writing a program that simulate a service desk. This service desk should be able to service 100 customers that can have one of three different priorities (high, medium, and low). The duration for any customer is a random number (between 5 minutes and 8 minutes). Code a modular program that uses parallel arrays to store priority levels and service times for 100 service requests. The program must do the following: The program must first ask the user to run the simulation or quit the program using a menu. This must be done using a function that is called. Upon input of the menu choice, if the user inputs a 2, the program will exit, otherwise if the user enters a 1, the program must begin processing the 100 service requests. The program must use loops and random numbers to generate priority level (high, medium, or low) as well as the service time (between 5 and 8 minutes) for each request in parallel arrays.…
int func(int a, int b) { return (a