def before (k, A) which takes an integer k and an array A of integers as inputs and returns a new array consisting of all the integers in A which come before the last occurrence of k in A, in the same order they are in A. For example, if A İS [1,2,3,6,7,2,3,4] then before (3,A) will return [1,2,3,6,7,2].Ifk does not occur in A, the function should return None.
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Using recursion, write a Python function
def before(k,A)
which takes an integer k and an array A of integers as inputs and returns a new array consisting of all the integers in A which come before the last occurrence of k in A, in the same order they are in A.
For example, if A is [1,2,3,6,7,2,3,4] then before(3,A) will return [1,2,3,6,7,2]. If k does not occur in A, the function should return None.
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- Write a Python function def isSubArray(A,B) which takes two arrays and returns True if the first array is a (contiguous) subarray of the second array, otherwise it returns False. You may solve this problem using recursion or iteration or a mixture of recursion and iteration. For an array to be a subarray of another, it must occur entirely within the other one without other elements in between. For example: [31,7,25] is a subarray of [10,20,26,31,7,25,40,9] [26,31,25,40] is not a subarray of [10,20,26,31,7,25,40,9] A good way of solving this problem is to make use of an auxiliary function that takes two arrays and returns True if the contents of the first array occur at the front of the second array, otherwise it returns False. Then, A is a subarray of B if it occurs at the front of B, or at the front of B[1:], or at the front of B[2:], etc. Note you should not use A == B for arrays.Using recursion, write a Python function: def replace (A, d, e) which takes as input an array of integers A, and two integers d and e, and changes A by replacing every occurrence of d with e. For example, if A is the array [10,0,2,0],replace (A,0,5) should change A to [10,5,2,5].Using recursion, write a Python function def countOdds(A) which which takes an array of integers A as input and returns the number of elements in the array that are odd. For example, if A is [1,2,5,3,6,5,3,5,5,4] the the function should return 7. If A is empty then it should return 3. Hint: To check if n is odd it suffices to check if dividing it by 2 gives remainder 1 (in Python, this remainder is calculated by n%2).
- Write a recursive function using python for the problem: A palindrome is a sequence of characters which is the same when the sequence is reversed. Given an array A indexed from p to q containing characters, determine if the sequence of characters in A[p..q] forms a palindrome. Return True is a palindrome is formed and return False if it does not.Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] Hint:The trick is to remove the last element each time to make the ArrayList a little shorter. import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum =…Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…
- write java codes to do the following: Write a recursive function to check if an integer array is negative symmetric, for example, an array of 10, 20, 30, 90, -30, -20, -10 is considered as negative symmetric, while an array of 10, 20, 30, 90, 30, 20, 10 is not considered as negative symmetric. public static boolean checkArraySym(int [ ] A, int first, int last) that receives an array A, first index, last index and checks if the array is negative symmetricImplement a recursive C++ function which takes an array of integers (arr) and the starting (start) and ending (end) indices of a portion (part) of this array, and returns the index of the second smallest element present in that portion of array arr. The prototype of your function should be: int findSecondSmallest (int* arr, int start, int end) For example, the function call findSecondSmallest(arr,3,8) should determine and return the index of the second smallest element present in the array arr between the indices 3 and 8 (both inclusive).An ascending array is an array such as "124678", “abcfgkl", and “5789", is in an increasing order. The empty array is regarded as an ascending array. Write a function 2. that every character bool isAscending (char* arr, int size) that returns true if this array is ascending. (a) Use iteration (b) Use recursion (c) Convert the function that you wrote in part (b) into a template function. The template function should work for arrays of any type.
- Implement a recursive C++ function which takes an integer array (A) and the starting (start) and ending(end) indices of that array, and returns the sum of all elements present in that array. The prototype ofyour function should be:int findSum (int* A, int start, int end)Write a Python function def excludeSum(A,f) that takes as input an array of integers A and a function f that takes an integer as input and returns a boolean. excludeSum should return the sum of all the elements of A apart from those "excluded" by f, that is, those on which f returns True. For example, the following code def isOdd(n): return n%2==1 A = [2,4,1,35,42,3,3] excludeSum(A,isOdd) should return the sum of the even elements of A, i.e. 48.Write a program using c# to do the following: Initialize an array A with 10 elements. Initialize an array B with 7 elements. Divide each element of array A with each element of array B that is a[0]/b[0] , a[1]/b[1] etc. Implement the same to handle divide by zero error and index out of bound error.