def ask_user(): Returns clean input of type string in all caps to the user :return: input string in all CAPS return "LOW"
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- /*** Adds letterGuessed to the current String updateLetterBoard* @param usedLetterBoard* @param letterGuessed* @param first* @return updateLetterBoard with letterGuess appended. */public static String updateLetterBoard(String usedLetterBoard, char letterGuessed, boolean first) {Write a function that reverses a string. The header of the function is: def reverse(s):Write a test program that prompts the user to enter a string, invokes the reverse function, and displays the reversed string.public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…
- Given string stringVal on one line, integer idxStart on a second line, and integer choiceLen on a third line, replace choiceLen characters with "1234", starting at index idxStart. Ex: If the input is: Fuzzy bear 3 4 then the output is: Fuz1234ear Note: Using a pre-defined string function, the solution can be just one line of code. #include <iostream>#include <string>using namespace std; int main() { string stringVal; int idxStart; int choiceLen; getline(cin, stringVal); cin >> idxStart; cin >> choiceLen; /* Your code goes here */ cout << stringVal << endl; return 0;}public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…Given the code:string s;cout << "Enter a string of any length: ";cin >> s; Write a few lines of code including a loop that will count and print the number of spaces in the string s using indexes.Note that s can be a string of any length.Example Output 1Enter a string of any length: Hi, how are you?3Example Output 2Enter a string of any length: I am going out tonight.4
- Command Line Args Modify code below to accept the values for the key as command line arguments. Your program may assume the arguments given at the command line are integers. If there are no arguments, print a message. If there is at least one argument, compute and print the average of the arguments. Note that you will need to use the parseInt method of the Integer class to extract integer values from the strings that are passed in. If any non-integer values are passed in, your program will produce an error, which is unavoidable at this point. import java.util.Scanner;import java.text.NumberFormat; public class Quizzes {// ----------------------------------------------// Read in the number of questions followed by// the key, then read in each student's answers// and calculate the number and percent correct.// ---------------------------------------------- public static void main(String[] args) {int numQuestions;int numCorrect;String anotherQuiz;int answer;NumberFormat percent…Q1__;. A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers. Given a string s, return true if it is a palindrome, or false otherwise. Example 1: Input: s = "A man, a plan, a canal: Panama" Output: true Explanation: "amanaplanacanalpanama" is a palindrome. Example 2: Input: s = "race a car" Output: false Explanation: "raceacar" is not a palindrome..please code in pythonis_phone_num: This Boolean function takes a string and returns True if it is in the formatddd-ddd-dddd, where d is a digit, False otherwise. Example calls:is_phone_num('123-456-7890') --> Trueis_phone_num('123-4556-7890') --> Falseis_phone_num('(123)456-7890') --> False
- Ex: Use getline() to get a line of user input into a string. Output the line. Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. Search the string (using find()) for common abbreviations and print a list of each found abbreviation along with its decoded meaning. Ex: Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. BFF: best friend forever IDK: I don't know Support these abbreviations: BFF -- best friend forever IDK -- I don't know . JK -- just kidding TMI -- too much information TTYL-talk to you later 1 #include 2 // FIXME include the string Library 3 using namespace std; 4 5 int main() { 6 7 8 9 10 } /* Type your code here. */ return 0; main.cpp7. username_ends_with_digits This function decides whether a given username ends with some digits. It returns either True, if the username does end with digits, or False, if it does not. Check out the .isdigit method on strings! Sample runs should look like: >>> username_ends_with_digits("FunctionEnjoyer") False >>> username_ends_with_digits("this_username_95060") Truepublic static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string