Date elian Genetics (continued) n Details Demonstrate the law of independent assortment by listing the 4 alleles that are produced when a pea plant with the genotype YyRr produces gametes. 1. 2. 4. 3. _ in the F1 and F2
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- More Crosses with Pea Plants: The Principle of Independent Assortment Given the following matings, what are the predicted phenotypic ratios of the offspring? a. AABb Aabb b. AaBb aabb c. AaBb AaBbMore Crosses with Pea Plants: The Principle of Independent Assortment In pea plants, long stems are dominant to short stems, purple flowers are dominant to white, and round peas are dominant to wrinkled. Each trait is determined by a single, different gene. A plant that is heterozygous at all three loci is self-crossed, and 2,048 progeny are examined. How many of these plants would you expect to be long stemmed with purple flowers, producing wrinkled peas?More Crosses with Pea Plants: The Principle of Independent Assortment In the following trihybrid cross, determine the chance that an individual could be phenotypically A, b, C in the F1 generation. P1: AaBbCc AabbCC
- More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible genotypes of the following parents by analyzing the phenotypes of their children. In this case, we will assume that brown eyes (B) is dominant to blue (b) and that right-handedness (R) is dominant to left-handedness (r). a. Parents: brown eyes, right-handed brown eyes, right-handed Offspring: 3/4 brown eyes, right-handed 1/4 blue eyes, right-handed b. Parents: brown eyes, right-handed blue eyes, right-handed Offspring: 6/16 blue eyes, right-handed 2/16 blue eyes, left-handed 6/16 brown eyes, right-handed 2/16 brown eyes, left-handed c. Parents: brown eyes, right-handed blue eyes, left-handed Offspring: 1/4 brown eyes, right-handed 1/4 brown eyes, left-handed 1/4 blue eyes, right-handed 1/4 blue eyes, left-handedMore Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross in pea plants, in which smooth pea shape is dominant to wrinkled, and yellow pea color is dominant to green. A plant with smooth yellow peas is crossed to a plant with wrinkled green peas. The offspring produced peas that were all smooth and yellow. What are the genotypes of the parents? What are the genotypes of the offspring?Crossing Pea Plants: Mendels Study of Single Traits An unspecified characteristic controlled by a single gene is examined in pea plants. Only two phenotypic states exist for this trait. One phenotypic state is completely dominant to the other. A heterozygous plant is self-crossed. What proportion of the progeny of plants exhibiting the dominant phenotype is homozygous?
- More Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross: P1: AABBCCDDEE aabbccddee F1: AaBbCcDdEe (self-cross to get F2) What is the chance of getting an AaBBccDdee individual in the F2 generation?Homozygous white grapefruit Heterozygous white grapefruit W Ww ww Ww Ww Ww ww Ww Ww 1. What will be the offspring, if the white grapefruit tree is heterozygous? 2. What will be the offspring, if the white grapefruit tree is homozygous? 3. What will be phonotypical ratio?SUNJECT - BIOLOGY (Genetics) × PROBABILITY. Based on the give question (PpYyRr * Ppyyrr) (SEE IMAGE), compute the following probabilities. Show your solutions. 1. Probability of PpYyRr 2. Probability of PPyyRr 3. Probability of at least exhibiting wrinkled seeds 4. Probability of at least exhibiting purple flowers 5. Probability of white flower, yellow and round seeds 6. Probability of having purple flowers and green seeds and round seeds 7. Probability of having white flower and yellow seed, or, white flower and wrinkled seed.
- Required information A heterozygous tall pea plant is allowed to self-fertillze. From the F1 progeny, a phenotyplcally tall plant was randomly chosen and mated to a phenotypically dwarf pea plant. What is the probability of producing any phenotyplcally dwarf plants from this mating? Multiple Choice 1/2 2/3 1/4 1/3 10 Show All MacBook AirThis problem leads you through the derivation of acorrected equation for RF in yeast tetrad analysis thattakes into account double crossover (DCO) meioses. A yeast strain that cannot grow in the absence ofthe amino acid histidine (his−) is mated with a yeaststrain that cannot grow in the absence of the aminoacid lysine (lys−). Among the 400 unordered tetrads resulting from this mating, 233 were PD, 11 wereNPD, and 156 were T.a. What types of spores are in the PD, NPD, andT tetrads?b. Are the his and lys genes linked? How do you know? c. Using the simple equation RF = 100 × [NPD +(1/2)T]/total tetrads, calculate the distance in mapunits between the his and lys genes.d. If you think about all the kinds of meiotic eventsthat could occur (refer to Fig. 5.24), you can seethat the calculation you did in part (c) may substantially underestimate RF. What kinds of meioses(NCO, SCO, or DCO) generated each of the tetradtypes in this cross? e. What incorrect assumptions does the simple RFequation…F1 hybrids between two species of cotton, Gossypium barbadenseand Gossypium hirsutum, are very vigorous plants. However, F1crosses produce many seeds that do not germinate and a high percentageof very weak F2 offspring. Suggest two reasons for theseobservations.