Data: INCLUDE UNITS!!! Barometric Pressure: A B C D 2 H,0,(aq) 759 forr Mass of 10 mL grad cylinder with ~5 ml H₂O: solution Mass of empty 10 mL grad cylinder Initial gas volume reading KI (cat.) Final gas volume reading 2 H₂0 (aq) + O₂(g) Trial 1 50.081 45.392 PBOR=759660 Trial 3 50.132 Trial 2 49.838 45.383 O O O 50ml 59 mil. 52ml. 45.943).

Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter1: Gases And The Zeroth Law Of Thermodynamics
Section: Chapter Questions
Problem 1.32E
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Data: INCLUDE UNITS!!!
Barometric Pressure:
A
B
C
D
E
F
G
H
1
J
K
L
M
N
Calculations: INCLUDE UNITS AND SHOW WORK (attach scratch paper or use back side of the page)!!!
Trial 1
Trial 2
Trial 3
0
P
2 H,0,(aq)
759 forr
Mass of 10 mL grad cylinder with ~5 mL
H₂O: solution
Mass of empty 10 mL grad cylinder
Initial gas volume reading
Final gas volume reading
Q
Temperature (°C)
Vapor pressure of water
(from Table 8-1)
Mass of H₂O₂ solution used
Volume of gas collected, in ml
Volume of gas collected, in L
Partial pressure of Oz, in torr
Partial pressure of O₂, in atm
Temperature (K)
Number of moles of Oz formed
Number of moles of H₂O₂ consumed
Mass of H₂O2 consumed
(molar mass = 34.02 g/mol)
Mass percent H₂0₂ in solution
KI (cat.)
Average mass % H₂O₂
15
16
17
18
19
20
21
22
23
2 H₂0 (aq) + O₂(g)
Trial 1
Trial 2
50.081 49-838
45.392 45.383
50ml. 59 mal
22.4°C 22.4°C
17.5
18.6
19.8
21.1
8-7
Temperature (°C) Vapor Pressure (torr) Temperature (°C)
12.8
13.6
14.5
15.5
16.5
PBaR=75968!
Trial 3
50-132
mperatures, in units of torr (760 torr = 1 atm).
Table 8-1: Vapor Pressure of Water at Various Temperatures
46.931.
O
52 ml.
22.42
24
25
26
27
28
29
30
31
32
*avie 0-1 lists the vapor pressure of water at
Vapor Pressure (torr)
22.4
23.8
25.2
26.7
28.3
30.0
31.8
33.7
35.7
Since the gas inside the graduated cylinder will contain both O2 and H₂0, the total pressure
exerted (which will be equal to the barometric pressure) will be due to the mixture.
Dalton's Law of Partial Pressures states that the total pressure exerted by a mixture of
gases is equal to the sum of the partial pressures of each mixture component:
Ptotal= Po₂+ PH₂0
(8)
Transcribed Image Text:Data: INCLUDE UNITS!!! Barometric Pressure: A B C D E F G H 1 J K L M N Calculations: INCLUDE UNITS AND SHOW WORK (attach scratch paper or use back side of the page)!!! Trial 1 Trial 2 Trial 3 0 P 2 H,0,(aq) 759 forr Mass of 10 mL grad cylinder with ~5 mL H₂O: solution Mass of empty 10 mL grad cylinder Initial gas volume reading Final gas volume reading Q Temperature (°C) Vapor pressure of water (from Table 8-1) Mass of H₂O₂ solution used Volume of gas collected, in ml Volume of gas collected, in L Partial pressure of Oz, in torr Partial pressure of O₂, in atm Temperature (K) Number of moles of Oz formed Number of moles of H₂O₂ consumed Mass of H₂O2 consumed (molar mass = 34.02 g/mol) Mass percent H₂0₂ in solution KI (cat.) Average mass % H₂O₂ 15 16 17 18 19 20 21 22 23 2 H₂0 (aq) + O₂(g) Trial 1 Trial 2 50.081 49-838 45.392 45.383 50ml. 59 mal 22.4°C 22.4°C 17.5 18.6 19.8 21.1 8-7 Temperature (°C) Vapor Pressure (torr) Temperature (°C) 12.8 13.6 14.5 15.5 16.5 PBaR=75968! Trial 3 50-132 mperatures, in units of torr (760 torr = 1 atm). Table 8-1: Vapor Pressure of Water at Various Temperatures 46.931. O 52 ml. 22.42 24 25 26 27 28 29 30 31 32 *avie 0-1 lists the vapor pressure of water at Vapor Pressure (torr) 22.4 23.8 25.2 26.7 28.3 30.0 31.8 33.7 35.7 Since the gas inside the graduated cylinder will contain both O2 and H₂0, the total pressure exerted (which will be equal to the barometric pressure) will be due to the mixture. Dalton's Law of Partial Pressures states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each mixture component: Ptotal= Po₂+ PH₂0 (8)
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