crossing father type O blood. 1. A baby with type Ab blood is born into a family where the mother has type B blood a (1) (ii) 2. Silky Determine whether the husband is the biological father of the baby. Explain your answer in (i) above. feathers in fowls are caused by an allele which is recessive to the allele for norm thers
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- . Assuming no involvement of the Bombay phenotype(in case you’ve already read ahead to Section 3.2):a. If a girl has blood type O, what could be the genotypes and corresponding phenotypes of her parents?b. If a girl has blood type B and her mother has bloodtype A, what genotype(s) and correspondingphenotype(s) could the other parent have?c. If a girl has blood type AB and her mother is alsoAB, what are the genotype(s) and correspondingphenotype(s) of any male who could not be thegirl’s father?făctőrs suc 19) The genotype of a black snake is unknown. Black is a dominant allele, so the snake could be either BB or Bb. You cross this snake with a white snake (bb). Which of the following results of that cross would support the unknown genotype of the black snake being a homozygote? A) All F1 offspring are white B) All F1 offspring are black C) Half of the F1 offspring are white, the other half are black D) Three-quarters of the F1 offspring are black, the other quarter are white В x bb the1. Two normal visioned parents have a color-blind son. Give the genotype of both parents and the son. 2. In cats, the allele (B) produces black color but (b) produces a yellow color. These alleles are incompletely dominant to each other. A heterozygote produces a tortoise shell color. The alleles (B) and (b) are sex-linked as well. Cross a tortoise shell female with a yellow male. a. What percent of their offspring will be yellow? b. What percent of their offspring will be black? c. What percent of their offspring will be tortoise shell? d. Why is it impossible to have a tortoise shell male offspring?
- 3. The recessive sex-linked gene (h) prolongs the blood-clotting time, resulting in the genetically inherited disease called hemophilia. From the information in the pedigree chart (right), answer the following questions: Hemophilia in humans (a) If 112 marries a normal man, what is the probability of her first child being a hemophiliac? 2 (b) Suppose her first child is actually a hemophiliac. What is the chance that her second child will be a boy with hemophilia? 2 (c) If I14 has children with a hemophiliac man, what is the probability that her first child will be phenotypically normal? (d) If the mother of 12 was phenotypically normal, what phenotype was her father? 4. The phenotypic expression of a dominant gene in Ayrshire cattle is a notch in the tips of the ears. In the pedigree chart on the right, notched animals are represented by the solid symbols. Ear notches in Ayrshire cattle Determine the probability of notched offspring being produced from the following matings: 1 2 (a)…Part B 1. For the remaining characteristics, you will be looking at homozygous and heterozygous traits. Each trait will be determined to be homozygous recessive, homozygous dominant, or hetero- zygous. Letters representing the alleles will be given to you; the uppercase letter is always dominant and the lowercase letter is always recessive. If both dice rolled are even numbers, it indicates homozygous dominant alleles; if both are odd, it indicates homozygous recessive alleles; if one is odd and the other even, it indicates heterozygous alleles. 2. Eyebrows: Use the alleles "A" and "a" for this trait. Two separate brows are the dominant trait, whereas the unibrow (or one continuous brow) is recessive. 3. Eye shape: Use the alleles "R" and "r" for this trait. Round eyes are the dominant trait; almond shaped eyes are recessive. 4. Hitchhiker's thumb: Use the alleles "H" and "h" for this trait. Straight thumbs are dominant; Hitchhiker's thumbs (the curving upward of the thumb) are…2) A researcher crossed a heterozygous yellow seed plant (Yy) and a recessive green seedplant (yy). Draw a Punnett Square and determine the genotype and phenotype ratios ofthe offspring.
- Part 2. Do one more example of a monohybrid cross. This time assign the letter "B" for onion taste. Being sweet is dominant controlled by allele (B) and being bitter is recessive-controlled by allele (b). Cross individuals who are both heterozygous for this trait. 5. What is the genotype of each of these heterozygous individuals? 6. What is the phenotype of these heterozygous individuals? Complete the Punnett square below using the alleles you just listed. 7. What are the resulting genotypes and their ratios or %? 8. What are the resulting phenotypes and their ratios or %? Figure 3. Monohybrid Cross for Onion Taste. 10338. Color blindness is a sex-linked recessive trait in humans. A woman who is a carrier for color blindnesS has children with a man who is color blind. Which of the following is true regarding their offspring? A. All sons are carriers. B. All sons are color blind. C. No daughters are color bl":... D. Any daughter is either color blind or a carrier 39. Predict what will be the possible phenotypic outcomes of an organism who is heterozygous for tallness (Tt) mated with a recessive (tt) individual? A. 3 tall offspring B. 4 tall offspring C. 4 dwarfs' offspring D.2 tall, 2 dwarfs' offspring 40. Which of the following is the major cause of wildlife depletion? A. Pollution B. Deforestation 41. Which is the correct formula in calculating population density? A. D = number of runs / total population B. D = population x area C. D = number of runs x total population D. D = pcpulation/area C. Overfishing D. Eutrophication1. Consider blue eyes (b) as a recessive trait to brown eyes (B). The presence of cheek dimples (D) is governed by dominant allele while absence (d) is controlled by a recessive one. A couple has heterozygous genotype for facial dimples, but the woman has blue eyes while the man is brown-eyed who has a blue-eyed mother. State the (a) phenotypes (b) phenotypic ratio of their progeny. (c) genotypic ratio
- 1. An albino man whose parents are both normal marries a woman ome of whose parents is normal and the other albino. She has an albino sister. The couple has a normal son. a.Is albinism a dominant or a recessive trait? Explain your answer B. Give genotypes of all the persons involved. C.The couple plans to have more kids. What is the probability of their second child being normal1. In a cross between a black and a white guinea pig, all members of the F1 generation are black. The F2 generation is made up of approximately 3/4 black and 1/4 white guinea pigs. (a) Diagram this cross, showing the genotypes and phenotypes. (b) What will the offspring be like if two F2 white guinea pigs are mated?1. Windows peak (S) is dominant over straight hairline (s). Given that the mother has heterozygous gene pair for window's peak and the father has straight hairline. a. What is the genotype of the mother? b. What is the genotype of the father? * How many kinds of gametes can the mother produce? List them down. d. How many kinds of gametes can the father produce? List them down. e. Perform a cross using a Punnett square. f. Give the genotypic ratio of the cross g. Give the phenotypic ratio of the cross A 4.