CREATE TABLE employees ( employee_number int NOT NULL, last_name char(50) NOT NULL, first_name char(50) NOT NULL, salary int, dept_id int, CONSTRAINT employees_pk PRIMARY KEY (employee_number) ); INSERT INTOo employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1001, 'Smith', 'John', 62000, 500); INSERT INTO employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1002, 'Anderson', 'Jack', 57500, 500); INSERT INTO employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1003, 'Everest', 'Brad', 71000, 501); INSERT INTO employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1004, 'Horvath', 'Jack', 42000, 501); PROBLEMS: 1. Create a select statement that will show all employees that have more than 50000 as their salary. 2. Create a select statement that will show all employees belonging into department 501. 3. Create a select statement that has a first name of Jack arranged them alphabetically in ascending order.

CREATE TABLE employees ( employee_number int NOT NULL, last_name char(50) NOT NULL, first_name char(50) NOT NULL, salary int, dept_id int, CONSTRAINT employees_pk PRIMARY KEY (employee_number) ); INSERT INTOo employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1001, 'Smith', 'John', 62000, 500); INSERT INTO employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1002, 'Anderson', 'Jack', 57500, 500); INSERT INTO employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1003, 'Everest', 'Brad', 71000, 501); INSERT INTO employees (employee_number, last_name, first_name, salary, dept_id) VALUES (1004, 'Horvath', 'Jack', 42000, 501); PROBLEMS: 1. Create a select statement that will show all employees that have more than 50000 as their salary. 2. Create a select statement that will show all employees belonging into department 501. 3. Create a select statement that has a first name of Jack arranged them alphabetically in ascending order.

A Guide to SQL

9th Edition

ISBN:9781111527273

Author:Philip J. Pratt

Publisher:Philip J. Pratt

Chapter6: Updating Data

Section: Chapter Questions

Problem 8SCG

See similar textbooks

Similar questions

DROP TABLE IF EXISTS Worker; CREATE TABLE Worker ( ); 0 INSERT ); WORKER_ID INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT, FIRST NAME TEXT, LAST NAME TEXT, SALARY INTEGER (15), JOINING DATE DATETIME, DEPARTMENT CHAR (25) INTO Worker (WORKER_ID, FIRST_NAME, LAST_NAME, SALARY, JOINING_DATE, DEPARTMENT) VALUES 'Arora', 100000, '14-02-20 09.00.00', 'HR'), (001, 'Monika', (002, 'Niharika', 'Verma' 80000, '14-06-11 09.00.00', 'Admin'), 'HR'), 'Admin'), Admin'), 'Account'), 'Kumar', 75000, '14-01-20 09.00.00', 'Account') DROP TABLE IF EXISTS Bonus; CREATE TABLE Bonus ( ); (003, 'Vishal' 'Singhal', 300000, '14-02-20 09.00.00', (004, 'Amitabh 'Singh', 500000, '14-02-20 09.00.00', (005, 'Vivek' 'Bhati', 500000, '14-06-11 09.00.00'. (006, 'Vipul', 'Diwan' 200000, '14-06-11 09.00.00', (007, 'Satish' (008, 'Geetika', 'Chauhan', 90000, '14-04-11 09.00.00', 'Admin'); WORKER_REF_ID INTEGER, BONUS AMOUNT INTEGER(10), BONUS_DATE DATETIME, FOREIGN KEY (WORKER_REF_ID) REFERENCES Worker (WORKER_ID) ON DELETE…
Database Q1: Which one of the following INSERT statements will successfully insert a single row? The following table has been created: CREATE TABLE student_table ( stud_id NUMBER (6), last_name VARCHAR2 (20), first_name VARCHAR2 (20), lunch_num NUMBER (4) ; a) INSERT VALUES INTO student_table (143354, ‘Roberts’, ‘Cameron’, 6543); b) INSERT INTO student_table COLMUNS (stud_id, last_name, lunch_num) VALUES (143352, ‘Roberts’, 5543, ‘Cameron’); c) INSERT TO student_table (stud_id, lunch_num, first_name, last_name) VALUES (143352, 6543, ‘Cameron’, ‘Roberts’); d) INSERT INTO student_table VALUES (143354, ‘Roberts’, ‘Cameron’, 6543); Q2: What does the following SQL statement display: SELECT EMP_ID, LAST_NAME, SALARY FROM EMPLOYEES WHERE SALARY > (SELECT MIN (E. SALARY) FROM EMPLOYEES E) ORDER BY SALARY DESC; a) Employees information who earn less money than the maximum salary b) Employees information who earn more money than the highest employee salary c) Employees information who earn…
SQL: THIS IS FIRST TABLE : create table emp ( eid number(7), fname char(20), lname char(20), salary number, primary key (eid) ); insert into emp values (1111111, 'ali', 'ahmed', 3500); insert into emp values(2222222, 'asma', 'dani', 2000); insert into emp values(3333333, 'hassan', 'ali', 4500); insert into emp values(4444444, 'khaled', 'shaalan',6000); insert into emp values(5555555, 'farhad', 'kokol', 7500); insert into emp values(6666666, 'amir', 'sheikh', 10000); insert into emp values(7777777, 'rahul', 'kolap', 11000); insert into emp values(8888888, 'halim', 'ziaey', 21000); insert into emp values(9999999, 'henna', 'bubaker', 30000); THIS IS SECOND TABLE : create table students ( sid number, fname char(20), lname char(20), avg number, age number, primary key (sid) ); insert into students values (1111111, 'ali', 'ahmed', 76, 21); insert into students values(2222222, 'asma', 'dani', 89, 20); insert into students values(3333333, 'hassan', 'ali', 67, 23); insert into…
CREATE TABLE DONORS (donor_id INT NOT NULL,donor_name varchar(255) NOT NULL,donor_age int,PRIMARY KEY (donor_id ));CREATE TABLE DONATIONS(pledge_id INT NOT NULL,pledge_date varchar(255) NOT NULL,amount_pledged int,Is_paid int,donor_id int,PRIMARY KEY (pledge_id ),FOREIGN KEY (donor_id) REFERENCES DONORS(donor_id)); 1. Populate every relation with three rows.
CREATE TABLE EMPLOYEE(ENUM DECIMAL(12) NOT NULL,/* Employee number */FNAME VARCHAR(50) NOT NULL,/* First name */LNAME VARCHAR(50) NOT NULL,/* Last name */DOB DATE NULL,/* Date of birth */CONSTRAINT EMPLOYEE_PKEY PRIMARY KEY(ENUM) );CREATE TABLE DRIVER(ENUM DECIMAL(12) NOT NULL,/* Employee number */LNUM DECIMAL(8) NOT NULL,/* Driving license number */STATUS VARCHAR(10) NOT NULL,/* Driver status */CONSTRAINT DRIVER_PKEY PRIMARY KEY(ENUM),CONSTRAINT DRIVER_UNIQUE UNIQUE(LNUM),CONSTRAINT DRIVER_FKEY FOREIGN KEY(ENUM) REFERENCES EMPLOYEE(ENUM),CONSTRAINT DRIVER_STATUS CHECK (STATUS IN ('AVAILABLE', 'BUSY', 'ON LEAVE')) );CREATE TABLE TRUCK(REGNUM VARCHAR(10) NOT NULL,/* Registration number */CAPACITY DECIMAL(7) NOT NULL,/* Capacity */WEIGHT DECIMAL(7) NOT NULL,/* Weight */STATUS VARCHAR(10) NOT NULL,/* Present status */CONSTRAINT TRUCK_PKEY PRIMARY KEY(REGNUM),CONSTRAINT TRUCK_STATUS CHECK( STATUS IN ('AVAILABLE', 'USED', 'MAINTAINED')),CONSTRAINT TRUCK_WEIGHT CHECK( WEIGHT > 0.0 AND…
CREATE TABLE EMPLOYEE(ENUM DECIMAL(12) NOT NULL,/* Employee number */FNAME VARCHAR(50) NOT NULL,/* First name */LNAME VARCHAR(50) NOT NULL,/* Last name */DOB DATE NULL,/* Date of birth */CONSTRAINT EMPLOYEE_PKEY PRIMARY KEY(ENUM) );CREATE TABLE DRIVER(ENUM DECIMAL(12) NOT NULL,/* Employee number */LNUM DECIMAL(8) NOT NULL,/* Driving license number */STATUS VARCHAR(10) NOT NULL,/* Driver status */CONSTRAINT DRIVER_PKEY PRIMARY KEY(ENUM),CONSTRAINT DRIVER_UNIQUE UNIQUE(LNUM),CONSTRAINT DRIVER_FKEY FOREIGN KEY(ENUM) REFERENCES EMPLOYEE(ENUM),CONSTRAINT DRIVER_STATUS CHECK (STATUS IN ('AVAILABLE', 'BUSY', 'ON LEAVE')) );CREATE TABLE TRUCK(REGNUM VARCHAR(10) NOT NULL,/* Registration number */CAPACITY DECIMAL(7) NOT NULL,/* Capacity */WEIGHT DECIMAL(7) NOT NULL,/* Weight */STATUS VARCHAR(10) NOT NULL,/* Present status */CONSTRAINT TRUCK_PKEY PRIMARY KEY(REGNUM),CONSTRAINT TRUCK_STATUS CHECK( STATUS IN ('AVAILABLE', 'USED', 'MAINTAINED')),CONSTRAINT TRUCK_WEIGHT CHECK( WEIGHT > 0.0 AND…
CREATE TABLE EMPLOYEE(ENUM DECIMAL(12) NOT NULL,/* Employee number */FNAME VARCHAR(50) NOT NULL,/* First name */LNAME VARCHAR(50) NOT NULL,/* Last name */DOB DATE NULL,/* Date of birth */CONSTRAINT EMPLOYEE_PKEY PRIMARY KEY(ENUM) );CREATE TABLE DRIVER(ENUM DECIMAL(12) NOT NULL,/* Employee number */LNUM DECIMAL(8) NOT NULL,/* Driving license number */STATUS VARCHAR(10) NOT NULL,/* Driver status */CONSTRAINT DRIVER_PKEY PRIMARY KEY(ENUM),CONSTRAINT DRIVER_UNIQUE UNIQUE(LNUM),CONSTRAINT DRIVER_FKEY FOREIGN KEY(ENUM) REFERENCES EMPLOYEE(ENUM),CONSTRAINT DRIVER_STATUS CHECK (STATUS IN ('AVAILABLE', 'BUSY', 'ON LEAVE')) );CREATE TABLE TRUCK(REGNUM VARCHAR(10) NOT NULL,/* Registration number */CAPACITY DECIMAL(7) NOT NULL,/* Capacity */WEIGHT DECIMAL(7) NOT NULL,/* Weight */STATUS VARCHAR(10) NOT NULL,/* Present status */CONSTRAINT TRUCK_PKEY PRIMARY KEY(REGNUM),CONSTRAINT TRUCK_STATUS CHECK( STATUS IN ('AVAILABLE', 'USED', 'MAINTAINED')),CONSTRAINT TRUCK_WEIGHT CHECK( WEIGHT > 0.0 AND…
LAB - Select horses with logical operators The Horse table has the following columns: • ID integer, primary key • RegisteredName - variable-length string • Breed - variable-length string • Height-decimal number • BirthDate - date Write a SELECT statement to select the registered name, height, and birth date for only horses that have a height between 15.0 and 16.0 (inclusive) or have a birth date on or after January 1, 2020.
1) Write the SQL code that will create the table structure for a table named EMP. This table is a subset of the EMPLOYEE table. The basic EMP table structure is summarized in the table below. (Note that the EMP_NUM is the PK)? ATTRIBUTE(FIELD) NAME DATADECLARATION Constraints EMP_NUM INT Auto generated Identifier, start from 101 EMP_LNAME VARCHAR(15) Not null EMP_FNAME VARCHAR(15) Not Null EMP_INITIAL CHAR(1) EMP_HIREDATE DATE Default value is system date JOB_CODE CHAR(3) Make sure input is in the range500,501,502
create table patients ( patient_id VARCHAR(255),name VARCHAR(255),insurance DECIMAL(15,2),date_admitted DATE,date_checked_out DATE,PRIMARY KEY(patient_id));INSERT INTO patients (ID , name , insurance , date_admitted , date_checked_out) values (2 , 'Ali' , '22.2' , '2/1/2020' , '3/1/2020')SELECT * FROM table patients create table doctor (doctor_id VARCHAR(255),name VARCHAR(255),specialization VARCHAR(255),PRIMARY KEY (doctor_id) ); create table test (test_id VARCHAR(255),test_name VARCHAR(255),test_date DATE,test_time TIME,result VARCHAR(255),PRIMARY KEY(test_id)); create table doctor_patient( patient_id VARCHAR(255), doctor_id VARCHAR(255),PRIMARY KEY(patient_id),FOREIGN KEY(doctor_id) REFERENCES doctor(doctor_id) ); create table test_log (test_log_id varchar(255),patient_id VARCHAR(255),test_id VARCHAR(255),doctor_id VARCHAR(255),comments VARCHAR(255),PRIMARY KEY(test_log_id),FOREIGN KEY(test_id) REFERENCES test(test_id),FOREIGN KEY(patient_id) REFERENCES…
create table patients ( patient_id VARCHAR(255),name VARCHAR(255),insurance DECIMAL(15,2),date_admitted DATE,date_checked_out DATE,PRIMARY KEY(patient_id));INSERT INTO patients (ID , name , insurance , date_admitted , date_checked_out) values (2 , 'Ali' , '22.2' , '2/1/2020' , '3/1/2020')SELECT * FROM table patients create table doctor (doctor_id VARCHAR(255),name VARCHAR(255),specialization VARCHAR(255),PRIMARY KEY (doctor_id) ); create table test (test_id VARCHAR(255),test_name VARCHAR(255),test_date DATE,test_time TIME,result VARCHAR(255),PRIMARY KEY(test_id)); create table doctor_patient( patient_id VARCHAR(255), doctor_id VARCHAR(255),PRIMARY KEY(patient_id),FOREIGN KEY(doctor_id) REFERENCES doctor(doctor_id) ); create table test_log (test_log_id varchar(255),patient_id VARCHAR(255),test_id VARCHAR(255),doctor_id VARCHAR(255),comments VARCHAR(255),PRIMARY KEY(test_log_id),FOREIGN KEY(test_id) REFERENCES test(test_id),FOREIGN KEY(patient_id) REFERENCES…
Question 5 Suppose that you have the following table: CREATE TABLE coupons ( coupon id INTEGER name VARCHAR2 (30) duration INTERVAL YEAR (3) TO MONTH Now, considers the following INSERT statement: INSERT INTO coupons (coupon id, name, duration) VALUES (4, 'BD1.5 Corn Flakes, INTERVAL 1- 3 YEAR TO MONTH) The above INSERT statement stores the following data: A. 4 BD1.5 Corn Flakes +000-14 4 BD1.5 Corn Flakes +014-00 4 BD1.5 Corn Flakes +014 None of the above