Consider the square channel shown in the sketch operating under steady state condition. The inner surface of the channel is at a uniform temperature of 600 K and the outer surface is at a uniform temperature of 300 K. From a symmetrical elemental of the channel, a two- dimensional grid has been constructed as in the right figure below. The points are spaced by equal distance. Tout = 300 K k = 1 W/m-K T = 600 K (a) The heat transfer from inside to outside is only by conduction across the channel wall. Beginning with properly defined control volumes, derive the finite difference equations for locations 123. You can also use (n, m) to represent row and column. For example, location Dis (3, 3), location is (3,1), and location 3 is (3,5). (hint: I have already put a control volume around this locations with dashed boarder.) (b) Please use excel to construct the tables of temperatures and finite difference. Solve for the temperatures of each locations. Print out the tables in the spread sheet. (hint: the red dots here is at constant temperature, 300 or 600 K. The black and blue ones are the ones to be solved. Black ones are edge ones, among which the ones on right is slightly different.)

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
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Chapter5: Analysis Of Convection Heat Transfer
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Problem 5.10P: 5.10 Experiments have been performed on the temperature distribution in a homogeneous long cylinder...
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Consider the square channel shown in the sketch operating under steady state condition. The inner surface of the
channel is at a uniform temperature of 600 K and the outer surface is at a uniform temperature of 300 K. From a
symmetrical elemental of the channel, a two-dimensional grid has been constructed as in the right figure
below. The points are spaced by equal distance.
Tout = 300 K
k = 1 W/m-K
T = 600 K
(a) The heat transfer from inside to outside is only by conduction across the channel wall. Beginning with
properly defined control volumes, derive the finite difference equations for locations 123. You can
also use (n, m) to represent row and column. For example, location Dis (3, 3), location is (3,1), and
location 3 is (3,5). (hint: I have already put a control volume around this locations with dashed boarder.)
(b) Please use excel to construct the tables of temperatures and finite difference. Solve for the temperatures
of each locations. Print out the tables in the spread sheet.
(hint: the red dots here is at constant temperature, 300 or 600 K. The black and blue ones are the ones to be
solved. Black ones are edge ones, among which the ones on right is slightly different.)
Transcribed Image Text:Consider the square channel shown in the sketch operating under steady state condition. The inner surface of the channel is at a uniform temperature of 600 K and the outer surface is at a uniform temperature of 300 K. From a symmetrical elemental of the channel, a two-dimensional grid has been constructed as in the right figure below. The points are spaced by equal distance. Tout = 300 K k = 1 W/m-K T = 600 K (a) The heat transfer from inside to outside is only by conduction across the channel wall. Beginning with properly defined control volumes, derive the finite difference equations for locations 123. You can also use (n, m) to represent row and column. For example, location Dis (3, 3), location is (3,1), and location 3 is (3,5). (hint: I have already put a control volume around this locations with dashed boarder.) (b) Please use excel to construct the tables of temperatures and finite difference. Solve for the temperatures of each locations. Print out the tables in the spread sheet. (hint: the red dots here is at constant temperature, 300 or 600 K. The black and blue ones are the ones to be solved. Black ones are edge ones, among which the ones on right is slightly different.)
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