Consider the solid that lies above the rectangle (in the xy-plane) R = [−2, 2] × [0, 2], 6y + 12. and below the surface z = x² (A) Estimate the volume by dividing R into 4 rectangles of equal size, each twice as wide as high, and choosing the sample points to result in the largest possible Riemann sum. Riemann sum= 40 (B) Estimate the volume by dividing R into 4 rectangles of equal size, each twice as wide as high, and choosing the sample points to result in the smallest possible Riemann sum. Riemann sum= 40 (C) Using iterated integrals, compute the exact value of the volume. Volume = 176/3

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter8: Further Techniques And Applications Of Integration
Section8.3: Volume And Average Value
Problem 22E
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Consider the solid that lies above the rectangle (in the xy-plane) R = [−2, 2] × [0, 2],
and below the surface z = x² - 6y + 12.
(A) Estimate the volume by dividing R into 4 rectangles of equal size, each twice as wide as high, and choosing the sample points to
result in the largest possible Riemann sum.
Riemann sum= 40
(B) Estimate the volume by dividing R into 4 rectangles of equal size, each twice as wide as high, and choosing the sample points to
result in the smallest possible Riemann sum.
Riemann sum= 40
(C) Using iterated integrals, compute the exact value of the volume.
Volume =
176/3
Transcribed Image Text:Consider the solid that lies above the rectangle (in the xy-plane) R = [−2, 2] × [0, 2], and below the surface z = x² - 6y + 12. (A) Estimate the volume by dividing R into 4 rectangles of equal size, each twice as wide as high, and choosing the sample points to result in the largest possible Riemann sum. Riemann sum= 40 (B) Estimate the volume by dividing R into 4 rectangles of equal size, each twice as wide as high, and choosing the sample points to result in the smallest possible Riemann sum. Riemann sum= 40 (C) Using iterated integrals, compute the exact value of the volume. Volume = 176/3
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