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Consider the reaction CH₂O(g) = H₂(g) + CO(g). Exactly 3.4E-2 moles of CH₂O were injected into a 250 mL flask. At equilibrium, [CH₂O]=6.2E-2 M. What is Ke for this reaction?

Consider the reaction CH₂O(g) = H₂(g) + CO(g). Exactly 3.4E-2 moles of CH₂O were injected into a 250 mL flask. At equilibrium, [CH₂O]=6.2E-2 M. What is Ke for this reaction?

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.17P: 7-17 If a certain reaction takes 16 h to go to completion at 10°C, what temperature should we run it...
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Consider the reaction CH₂O(g) = H₂(g) + CO(g). Exactly 3.4E-2 moles of CH₂O were injected into a 250 mL flask. At equilibrium, [CH₂O]=6.2E-2 M. What is Ke for this reaction? ir notation (Uso Enotation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10°)
Transcribed Image Text:Consider the reaction CH₂O(g) = H₂(g) + CO(g). Exactly 3.4E-2 moles of CH₂O were injected into a 250 mL flask. At equilibrium, [CH₂O]=6.2E-2 M. What is Ke for this reaction? ir notation (Uso Enotation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10°)
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