Consider the reaction below which was carried out at 200.0 K to produce liquid ammonia: N2(g) + 3H2(g) ---> 2NH3() Suppose 37.3 g of N2 gas is mixed with 37.3 g of H2 gas. What is the volume (in units of liters) of gas remaining after the reaction is completed? The remaining gas was measured to have a temperature of 200.0 K and a pressure of 760.0 mmHg? molar mass of N2 = 28.013 g/mol molar mass of H2 = 2.0158 g/mol. Recall: Va (1/P) (at constant T and n) VaT (at constant Pand n) Van(at constant T and P) PV = nRT rate of effusion o 1 atm = 760 torr = 760 mmHg R-8.31446 J - K-1. mol-1 R= 0.0820573L-atm- K-1. mol-1

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Chapter5: Gases
Section: Chapter Questions
Problem 165MP
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Consider the reaction below which was carried out at 200.0 K to produce liquid ammonia:
N2(8) + 3H,(g)
2NH3()
Suppose 37.3 g of N2 gas is mixed with 37.3 g of H2 gas. What is the volume (in units of liters) of gas remaining after the reaction is completed?
The remaining gas was measured to have a temperature of 200.0 K and a pressure of 760.0 mmHg?
molar mass of N2= 28.013 g/mol
molar mass of H2 = 2.0158 g/mol.
%3D
Recall:
Vo (1/P) (at constant Tand n)
VaT (at constant P and n)
Van (at constant Tand P)
PV = nRT
rate of effusion ox
1 atm 760 torr 760 mmHg
%3D
%3D
R=8.31446 J K-1.r
mol-1
R= 0.0820573L atm K-1. mol-1
%3D
Transcribed Image Text:Consider the reaction below which was carried out at 200.0 K to produce liquid ammonia: N2(8) + 3H,(g) 2NH3() Suppose 37.3 g of N2 gas is mixed with 37.3 g of H2 gas. What is the volume (in units of liters) of gas remaining after the reaction is completed? The remaining gas was measured to have a temperature of 200.0 K and a pressure of 760.0 mmHg? molar mass of N2= 28.013 g/mol molar mass of H2 = 2.0158 g/mol. %3D Recall: Vo (1/P) (at constant Tand n) VaT (at constant P and n) Van (at constant Tand P) PV = nRT rate of effusion ox 1 atm 760 torr 760 mmHg %3D %3D R=8.31446 J K-1.r mol-1 R= 0.0820573L atm K-1. mol-1 %3D
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