Consider the QAM signal: m(t) = m1(t) cos(wt) + ma(t) sin(wt) with the carrier frequency w being much higher than the bandwidths of m(t) and ma(t). The in-phase part, m1(t) is recovered by multiplying the signal, m(t), with a frequency- imperfect carrier c(t) = cos(w+ dw)t and passing through a low-pass filter. Find the recovered signal. 1 zm(t) cos dut + ma(t) sin durt 1 b. zma(t) cos dut +m(t) sin dut 1 zmalt) cos but -m() sin dut с. Swt d. None

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13)
Consider the QAM signal: m(t) = m1(t) cos(wt) + m2(t) sin(wt) with the carrier
frequency w being much higher than the bandwidths of mi(t) and ma(t). The
in-phase part, m1(t) is recovered by multiplying the signal, m(t), with a frequency-
imperfect carrier e(t) = cos(w + dw)t and passing through a low-pass filter. Find the
recovered signal.
1
1
5mi(t) cos dut +ma(t) sin dust
a.
1
1
b.
5ma(t) cos dut +5m(t) sin dwt
ma(t) cos but - mi(t) sin dut
с.
d. None
Transcribed Image Text:13) Consider the QAM signal: m(t) = m1(t) cos(wt) + m2(t) sin(wt) with the carrier frequency w being much higher than the bandwidths of mi(t) and ma(t). The in-phase part, m1(t) is recovered by multiplying the signal, m(t), with a frequency- imperfect carrier e(t) = cos(w + dw)t and passing through a low-pass filter. Find the recovered signal. 1 1 5mi(t) cos dut +ma(t) sin dust a. 1 1 b. 5ma(t) cos dut +5m(t) sin dwt ma(t) cos but - mi(t) sin dut с. d. None
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