Consider the following switch statement where x is an int, answer the question below: switch (x) { case 3 : x += 1; case 4 : x += 2; case 5 : x += 3; case 6 : x++; case 7 : x += 2; case 8 : x--; case 9 : x++; } If x is currently equal to 3, what will the value of x be after the switch statement executes? Group of answer choices 5 6 10 11 12
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Consider the following switch statement where x is an int, answer the question below:
switch (x)If x is currently equal to 3, what will the value of x be after the switch statement executes?
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- X3: inlTo10 Write a function in Java that implements the following logic: Given a number n, return true if n is in the range 1..10, inclusive. Unless "outsideMode" is true, in which case return true if the number is less or equal to 1, or greater or equal to 10.22. What is the value of x after the following statements are executed? int x = 5; switch(x) { case 5: x += 2; case 6: x++; break; default: x *= 2; break; }Lowest Score Drop Write a program that calculates the average of a group of test scores, where the lowest score in the group is dropped. It should use the following functions: void getScore() should ask the user for a test score, store it in a reference parameter variable, and validate it. This function should be called by main once for each of the five scores to be entered. void calcAverage() should calculate and display the average of the four highest scores. This function should be called just once by main and should be passed the five scores. int findLowest() should find and return the lowest of the five scores passed to it. It should be called by calcAverage, which uses the function to determine which of the five scores to drop. Input Validation: Do not accept test scores lower than 0 or higher than 100.
- C++ A dice game called "21" It is a variation on BlackJack where one player plays against the computer trying to get 21 or as close to 21 without going over. Here are the rules of the game: You will play with dice that have numbers from 1 to 11. To win, the player or the computer has to get to 21, or as close as possible without going over. If the player or computer goes over 21, they instantly lose. If there is a tie, the computer wins. Starting the game: The player is asked to give the computer a name. For now, we'll simply call the computer opponent, "computer." The game starts with rolling four dice. The first two dice are for the player. These two dice are added up and the total outputted to the screen. The other two dice are for the computer. Likewise, their total is outputted to the screen. Player: If a total of 21 has been reached by either the player or the computer, the game instantly stops and the winner is declared. Otherwise, the player is asked if they…C++: Describe how the following call by reference works. Make a comment for each line. void pxc(int& c, int& d) { int k = c; c = d; d = k; } int main() { int a = 15, b = 100; pxc(a, b); }X15: inOrder Write a function in Java that implements the following logic: Given three ints, a, b , and c,return true if b is greater than a, and c is greater than b.However, with the exception that if bok is true, b does not need to be greater than a.
- 9- The script in the left side is used to solve the right-side equation. * #include #include using namespace std; int main(){ int x,y,z; cin>>x; switch(x){ (3.x-7)if (x=-5) Y= (5x² )if (x= 2)or(x= 5) (x-4x' )if (x=-4)or(x= 4)] case -5: y=3*x-7; cout<#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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