Consider the following mechanism for the enzyme- catalyzed reaction: E + SES ES 2 E + P (fast equilibrium) (slow) Derive an expression for the rate law of the reaction in terms of the concentrations of E and S. (Hint: To solve for [ES], make use of the fact that, at equilib- rium, the rate of forward reaction is equal to the rate of the reverse reaction.)

Consider the following mechanism for the enzyme- catalyzed reaction: E + SES ES 2 E + P (fast equilibrium) (slow) Derive an expression for the rate law of the reaction in terms of the concentrations of E and S. (Hint: To solve for [ES], make use of the fact that, at equilib- rium, the rate of forward reaction is equal to the rate of the reverse reaction.)

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter11: Chemical Kinetics: Rates Of Reactions

Section11.7: Reaction Mechanisms

Problem 11.12E

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