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- Scrabble Scrabble is a game where players get points by spelling words. Words are scored by adding together the point values of each individual letter. Define a function scrabble_score (word:str) -> int that takes a string word as input and returns the equivalent scrabble score for that word. score = {"a": 1, "c": 3, "f": 4, "i": 1, "1": 1, "o": 1, "r": 1, "u": 1, "t": 1, "x": 8, "z": 10} For example, "b": 3, "h": 4, "n": 1, Your Answer: == 20 assert scrabble_score("quick") assert scrabble_score("code") == 7 1 # Put your answer here 2 Submit "e": 1, "d": 2, "g": 2, "k": 5, "j": 8, "m": 3, "q": 10, "p": 3, "s": 1, "w": 4, "v": 4, "y": 4,In C++ how does a beginner level programmer create a function that will take a random word from a dynamic string array and hide the word for the user to guess letter by letter? If the user guesses the letter correctly, then the program will reveal only the correctly guessed letter of the world while the rest are blocked until the full word is guessed correctly. For example -> if the word is "world" then it could appear as "*****" and if the letter 'r' is guessed then it would show "****" and so on until the full word is revealed.function [P, A] = rect(L, W) P= 2 (L+ W); A =L*W; end Above function is defined to find perimeter and area of a rectangle. If a rectangle has length 10 mm and width 7 mm then the correct way to get perimeter and area of a given rectangle by executing this function is Select one: a. [A, B] = rect(10, 7) b. rect(7, 10) c. [A, B] = rect(7, 10) d. rect(10, 7)
- Here is a function that is supposed to return True if word (any string) ends with "s" and False otherwise: def ends_with_s(word):if len(word) < 1:return False return word[-1] == "s" Here is the test function I am using to test ends_with_s: def test_ends_with_s(): assert(ends_with_s("cats")) # option 1 assert(ends_with_s("") is False) # option 2 assert(ends_with_s("apple") is False) # option 3 assert(ends_with_s("S")) # option 4 Rewrite ends_with_s so that the test passesThe function “reverse” reverses a given string and returns a pointer to the resulting string. Complete the missing parts. char* reverse( char* str ) { int n, h, j, k; char _________________; n = strlen( _____________); h = (n / 2); for ( j=0, k=(n - 1); (j < h); j++, _____________________ ) { tmp = ___________; str[k] = str[j]; str[j] = _______________________________; } return ________________________;} int main( int argc, char** argv ) { char s[512]; strcpy( s, argv[1] ); printf( "Reverse: %s\n", reverse( s ) ); return 0;}Creat a class reversit and Write a function called reversit () that reverses a C-string (an array of char). Use a forloop that swaps the first and last characters, then the second and next-to-last characters, and so on. The string should be passed to reversit () as an argument. Write a program to exercise reversit (). The program should get a string from the user, call reversit (), and print out the result.by using c++
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- Q4. Write a program that read 2 matrices and has a function which finds their sum. Q5. Write a program that read 2 matrices and has a function which finds their multiplication. Q6. Write a program that handles a list of numbers where it has the following functions - Function that finds their average and sum - Function that finds their maximum and minimum - Function that search for a given number in that list. - Function that count the occurrence of a given number in that list. Then the program should do the following: - Read the list - Find the average and the sum of that list - Find the minimum and the maximum of that list - Count the occurrence of a given number in that list.// MichiganCities.cpp - This program prints a message for invalid cities in Michigan. // Input: Interactive // Output: Error message or nothing #include <iostream> #include <string> using namespace std; int main() { // Declare variables string inCity; // name of city to look up in array const int NUM_CITIES = 10; // Initialized array of cities string citiesInMichigan[] = {"Acme", "Albion", "Detroit", "Watervliet", "Coloma", "Saginaw", "Richland", "Glenn", "Midland", "Brooklyn"}; bool foundIt = false; // Flag variable int x; // Loop control variable // Get user input cout << "Enter name of city: "; cin >> inCity; // Write your loop here // Write your test statement here to see if there is // a match. Set the flag to true if city is found. // Test to see if city was not found to determine if // "Not a city in Michigan" message should be printed.…Language: JAVA Script Write a function 'mostFrequentLetter(string)' that takes a string as an argument and returns the character that appears the most often. In case of a tie, you may return any of the characters. The string will have at least one character. Examples: console.log(most Frequent Letter ("apple")); // "p" console.log(mostFrequentLétter("banana")); // "a" console.log(mostFrequentLetter("What about a longer string?")); //" " **************************************************************/ function mostFrequentLetter(string) { |// Your code here} /****DO NOT MODIFY ANYTHING UNDER THIS LINE****/ try{| module.exports = mostfrequentletter;}catch (e) {|module.exports=null;}