Consider the following code in C syntax, (use static scoping) #include #include int bar(int a, int b) { int i = a + b; a = a + 1; return i + b; } void foo(int a, int* b) { int c[3] {0, 1, 2}; %3D int i = 0; a = i; = malloc (sizeof (int)); *b = 42; c[2] = %3D bar(i, c[i]) ; printf ("%d-% d \n", a, *b); printf ("%d-%d - % d \n", c[0], c[1], c [2]); int main () { int x = 10; int* y = malloc (sizeof (int)); %3! *y 20; %3D foo(x, y); printf("%d-% d \n", x, *y); return x; } • If parameters are passed by reference, the out put of this program is (draw box and circle)

EBK JAVA PROGRAMMING
9th Edition
ISBN:9781337671385
Author:FARRELL
Publisher:FARRELL
Chapter2: Using Data
Section: Chapter Questions
Problem 14RQ
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Can someone help me with this problem? I can explain it but not sure what diagram to draw.
PROBLEM
Consider the following code in C syntax, (use static scoping)
#include <stdio.h>
#include <stdlib.h>
int bar(int a, int b)
{
int i = a + b;
a = a +
1;
return i + b;
}
void foo (int a, int* b)
{
int c[3] = {0, 1, 2};
int i = 0;
a = i;
b = malloc(sizeof (int));
*b = 42;
c[2] = bar(i, c[i]);
printf ("%d-% d \n", a, *b);
printf ("%d-%d - % d \n " , c[0], c[1], c [2]);
}
int main ()
{
int x
10;
int* y = malloc(sizeof (int));
20;
*y =
foo (x, у);
printf ("%d-% d \ n " , x, *y);
return x;
}
• If parameters are passed by reference, the out put of this program is (draw box and circle)
Transcribed Image Text:PROBLEM Consider the following code in C syntax, (use static scoping) #include <stdio.h> #include <stdlib.h> int bar(int a, int b) { int i = a + b; a = a + 1; return i + b; } void foo (int a, int* b) { int c[3] = {0, 1, 2}; int i = 0; a = i; b = malloc(sizeof (int)); *b = 42; c[2] = bar(i, c[i]); printf ("%d-% d \n", a, *b); printf ("%d-%d - % d \n " , c[0], c[1], c [2]); } int main () { int x 10; int* y = malloc(sizeof (int)); 20; *y = foo (x, у); printf ("%d-% d \ n " , x, *y); return x; } • If parameters are passed by reference, the out put of this program is (draw box and circle)
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