Consider the following block. Assume call-by-value parameter passing.
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- int func(int a, int b) { return (aint j; for (int i = 0; i < 5; i++) {j = 2*j*i;} What is j?int f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?#include using namespace std; (а) class Fraction{ int x, y; public: Fraction (int a, int b) {x=a; y=b;}; int getx(){return x;} int gety() {return y;} } ; int main() Fraction n(3, 7); ++n; cout << "x/y: " <« n.getx()<< "/" « n.gety()<#include<stdio.h> #include<stdarg.h> void fun1(int num, ...); void fun2(int num, ...); int main() { fun1(1, "Apple", "Boys", "Cats", "Dogs"); fun2(2, 12, 13, 14); return 0; } void fun1(int num, ...) { char *str; va_list ptr; va_start(ptr, num); str = va_arg(ptr, char *); printf("%s ", str); } void fun2(int num, ...) { va_list ptr; va_start(ptr, num); num = va_arg(ptr, int); printf("%d", num); }.3: The code on the right is supposed to be the ARM code for procA; however, there are problems with the ARM code. C code: int procA(int x, int y) { int perimeter = (x + y) * 2; I return perimeter; } ARM code: I procA: add rø, r1, r2 mov r1, rø lsl #1 bx lr push {lr} Give the corrected version of the ARM code for procA:int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;For the C++ program show on the next page, answer the questions that follow. The names g, j, x, and y are declared multiple times. Distinguish uses of these names using line numbers where they were declared as subscripts. a. At point A in the program, what names are in scope? b. At point A in the program, what variables are live? c. At point B in the program, what names are in scope? d. At point B in the program, what variables are live?int fun(int k){ return ( ); void main(){ int n; cin >> n; n = n * fun(n); <-- 1 Fill in the appropriate statement and expression in fun, so that when it is called in main, and after the execution of the statement marked 1, the value of n would always be n3.X15: inOrder Write a function in Java that implements the following logic: Given three ints, a, b , and c,return true if b is greater than a, and c is greater than b.However, with the exception that if bok is true, b does not need to be greater than a.CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;Q1 function myFunc() { let a = 10; if (true) { Q3 } } let a = 5; console.log(a); Q4 console.log(a); Q2 const square = num => num * num; console.log(square(3) + 5); myFunc(); let x = 30; let y "200"; console.log(x+y); const nums = [10, 20, 8, 17]; nums.filter(e=> e > 10); console.log(nums); Q5 const nums = [30, 35, 42, 20, 15]; console.log(nums.every (num => num > 20)); January 15SEE MORE QUESTIONSRecommended textbooks for youEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENTEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT