Consider an 8-m long simply supported T-beam with overhangs loaded as shown below. 200 mm w kN/m 50 mm 50 kN-m 50 kN-m 200 mm 2 m 4 m 2 m 50 mm 1. Determine the location of the neutral axis measured from the top of the beam and the moment of inertia (in mm4) of the section about its neutral axis.
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- The Z-section of Example D-7 is subjected to M = 5 kN · m, as shown. Determine the orientation of the neutral axis and calculate the maximum tensile stress c1and maximum compressive stress ocin the beam. Use the following numerical data: height; = 200 mm, width ft = 90 mm, constant thickness a = 15 mm, and B = 19.2e. Use = 32.6 × 106 mm4 and I2= 2.4 × 10e mm4 from Example D-7A simple beam ACE is constructed with square cross sections and a double taper (see figure). The depth of the beam at the supports is dAand at the midpoint is dc= 2d 4. Each half of the beam has length L. Thus, the depth and moment of inertia / at distance x from the left-hand end are, respectively, in which IAis the moment of inertia at end A of the beam. (These equations are valid for .x between 0 and L, that is, for the left-hand half of the beam.) Obtain equations for the slope and deflection of the left-hand half of the beam due to the uniform load. From the equations in part (a), obtain formulas for the angle of rotation 94at support A and the deflection Scat the midpoint.Two identical, simply supported beams AB and CD are placed so that they cross each other at their midpoints (sec figure). Before the uniform load is applied, the beams just touch each other at the crossing point. Determine the maximum bending moments (mab)max* and (MCD)max beams AB and CD, respectively, due to the uniform load if the intensity of the load is q = 6.4 kN/m and the length of each beam is L = 4 m.
- Draw the shear force and bending moment diagrams for the beam with loading shown below, P= 16 kN, w= 30 kN/m, M=40 kN.m. Also, state the maxmium shear force and bending moment in the text box. (Upload the diagrams showing all key values with units as well as neat and clear calculations) P kN P kN w kN/m M KN.m A 0.5 m 1 m 1 m- 1 m- -1 mEstablish the Shear & Moment Equation and Diagram of the loaded beam shown. Consider the Left Body Diagram of each section in establishing the equations. Draw and label the figure properly. Locate the maximum moment and the point of inflection. Figure: 5 kN/m 5 m 12 kN 50 kN-m n D B 2.5m C 2.5 m1. 2. 10 mm 10 mm 3. 5 mm 100 mm A beam section as shown in the sketch is subjected to a bendingmoment of Mx = 4 kN.m and a shear force of V = 2.5KN. 50 mm 100 mm Calculate the position of the centroid and the the second moment of area of the section about the sentroid horizontally. Draw the bending stress distribution through the height of the beam by calculating the bending stress at the critical positions Draw the shear stress distribution trough the height of the beam by calculating the shear stress below the flanges and at the centroid. 4. Draw the stress condition below the flanges, at the centroid and at the top and bottom of the beam.(7) 5. Draw the shearflow through the section. Show calculations
- For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M for any location in the beam. (Place the origin at point A.) Let a=2.50 m, b=4.25 m, PB = 45kN, and Pc = 90kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Answers: Ay = Dy= Mi i B Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) PB a PB B a Pc a Pc C kN b KN b D X D₂ XFor the beam shown, derive the expressions for shear and moment. Show complete solutions. Simplify all equations. Then draw the shear force and bending moment diagrams below the load diagram. Draw to scale. 1. Shear and Moment Diagram: 18 kN/m 25 kN-m A E |C ImIm - 2 m 3 m· Shear Equation Moment Equation Segment AB Segment BC Segment CD Segment DE Point of Zero Shear: Moment at point of zero shear:For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M for any location in the beam. (Place the origin at point A.) Let a=2.75 m, b=5.00 m, PB = 60KN, and Pc = 80kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Answers: Ay = Dy= tel tel a i B a Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) PB B a PB Pc a C Pc C KN b KN D b D X D₂ X
- A beam is supported and loaded as shown. In the section of the beam between 'A' and 'B', the equation for the resisting bending moment was determined as: M₁ = -6.5x²+50x. Determine the magnitude of maximum resisting bending moment (Mr,max) in the section. Note: Do NOT include units in your answer Answer: AA BFor the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=11.0 ft, b-4.5 ft, c= 7.5 ft, w = 4 kips/ft and M = 250 kip-ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. 27 W Ay a b Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) W M a B M C b C C₂ C -XThe simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A