Consider a cell undergoing the reaction below at 298 K 2 Na (s) + Cd²+(aq) <=> 2 Na+ (aq) + Cd (s) When [Na] 0.0005 molal (y=0.974) and [Cd²+] = 0.2 molal (y 0.102), then Ecell =+2.45 V. What is Eº for the cell =
Consider a cell undergoing the reaction below at 298 K 2 Na (s) + Cd²+(aq) <=> 2 Na+ (aq) + Cd (s) When [Na] 0.0005 molal (y=0.974) and [Cd²+] = 0.2 molal (y 0.102), then Ecell =+2.45 V. What is Eº for the cell =
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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.128QP: a Calculate G for the following cell reaction: Tl(s)Tl+(aq)Pb2+(aq)Pb(s) The Gf for Tl+(aq) is 32.4...
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![Consider a cell undergoing the reaction below at 298 K
2 Na (s) + Cd²+ (aq) => 2 Na¹(aq) + Cd (s)
When [Na]
0.0005 molal (y=0.974) and [Cd²+]
0.102), then Ecell =+2.45 V. What is Eº for the cell
=
=
0.2 molal (y=
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F806b78c5-9900-4411-98f9-2789e3c4ff7a%2F819cfc4c-e6e2-4211-9ab2-ce905feca11a%2Fv2wjja_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider a cell undergoing the reaction below at 298 K
2 Na (s) + Cd²+ (aq) => 2 Na¹(aq) + Cd (s)
When [Na]
0.0005 molal (y=0.974) and [Cd²+]
0.102), then Ecell =+2.45 V. What is Eº for the cell
=
=
0.2 molal (y=
=
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