Consider a 10-4 molar Fe2* solution at pH 2. Determine the corresponding pɛ when this solution is in equilibrium with: (a) Magnetite (b) Elemental iron Given: Fe = Fe2+ + 2e- log K = 16.17 Fe3O4 + 8H* + 2e = 3FE2+ + 4H2O log K = 36.81 %3D

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Problem #3
Consider a 10-4 molar Fe?+ solution at pH 2. Determine the corresponding pɛ when this
solution is in equilibrium with:
(a) Magnetite
(b) Elemental iron
Given: Fe = Fe²+ + 2e
log K = 16.17
Fe304 + 8H* + 2e = 3FE2+ + 4H2O
log K = 36.81
Transcribed Image Text:Problem #3 Consider a 10-4 molar Fe?+ solution at pH 2. Determine the corresponding pɛ when this solution is in equilibrium with: (a) Magnetite (b) Elemental iron Given: Fe = Fe²+ + 2e log K = 16.17 Fe304 + 8H* + 2e = 3FE2+ + 4H2O log K = 36.81
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