Consider 2 forces acting on a mass of 2.64 kg. F1 = 10.8 N @ 24.8 degrees and F2 = 6.96 N @ 66.1 degrees where the angles are measured relative to the +x direction. What is the magnitude of the acceleration produced considering only these 2 forces acting?
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- consider a force vector = 300 g at the 40º angle. resolve this vector into its x- and y-components by the following methods: a) graphical: make the x- and y-axes. use a scale of 30 g = 1.0 cm, and draw an arrow of appropriate length at 40º. drop perpendiculars from the tip of the vector to the x- and y-axes. measure the lengths of these lines and hence find the magnitudes of fx and fy. (do not calculate using trigonometry) record the results. b) analytical: compute the magnitudes of fx and fy by using the component method (equations 3-3 and 3-4). record the results.Two forces of F₁ = 112 √2 N and F₂ = 388 √2 What is the resultant force in terms of the force vectors F₁ and F2? What is the magnitude of an equal and opposite force, F3, which balances the first two forces? sin() cos() tan() T HOME cotan() acos EM4 asin() atan() acotan() sinh() 7 8 9 5 6 1 2 3 * 0 END cosh() tanh() cotanh() ⒸDegrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Given your observations from parts a and b, if working with vectors in 3 dimensions (i, j, k); what will the normalizing term n be for (i- j+ k) (i − j+ k) the two vectors F₁ = C₁ N and F₂ = 0₂ N. √T | Fren | Given the normalizing term n found in the previous part in 3 dimensions (i, j, k); what will the magnitude of the resultant vector be in terms of the constants c₁ and ₂. (i − j+ k) (i- j+k) The vectors in question are F₁: N and F₂ = 0₂ √√T √π F3 = = C1 N act on an object.Assume that all quantities are good to 3 significant figures...do not start rounding off too early or too much! All numeric answers should be entered rounded to 3 significant figures and assuming proper SI Units unless otherwise stated. Consider just these 2 forces acting on a mass of 2.79 kg. F1 = 8.36 N @ 21.5 degrees and F2 = 6.80 N @ 76.7 degrees where the angles are measured relative to the +x direction. What is the magnitude of the acceleration produced considering only these 2 forces acting?
- There are two forces on the 2 kg box in the overhead view of the figure, but only one is shown. For F1 20N, a = 12m/s² and 0 = 30°. A) Find the second force in unit-vector notation B) Find the angle between the second force and the x- axis.Three force vectors act on a free body at the origin as shown. F1= 4 N F2=2.0 i + 3.1 J N F3= 6.3 N at 35° relative to positive x axis. a) Report the unit vector in the direction of F3 (in unit vector or i,j,k notation to 4 sig figs) b)Calculate the resultant force R, which is the sum of the three forces F1,F2, and F3 (in unit vector or i,j,k notation to 4 sig figs)wo forces are acting on a 1.08 kg object. One force is directed completely in the negative x direction and has a magnitude of 8.3 N, The second force has a magnitude of 7.5 N and is directed 28∘28∘ to the right of the negative y axis. Assume standard Cartesian coordinates. Find the magnitude of the acceleration of the object
- At what angle must the 330-lb force be applied in order that the resultant R of the two forces have a magnitude of 1000 lb? For this condition what will be the angle ß between R and the horizontal? 330 lb 770 lb Answers: 0 = 8 B = i 0ment Chapter 05, Problem 007 There are two forces on the 1.82 kg box in the overhead view of the figure but only one is shown. For F, = 20.0 N, a = 13.5 m/s², and 0 = 21.5°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.) (a) Number i + jUnits (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work SUBMIT ANSWER SAVE FOR LATER Question Attempts: 0 of 10 usedVECTOR ADDITION: Find the sum of two ‘forces’: 100 g at 30º and 200 g at 120º, by: A) Graphical Method: Make the X- and Y-axes. Use a scale of 25 g = 1.0 cm. Draw arrows of appropriate lengths at 30º and 120º, both starting from the origin. Add them using the Parallelogram method. Measure the length and angle of the resultant. Convert length to magnitude of the resultant vector using the scale used to draw the vectors. Record the results in the Data Table. B) Analytical Method: Compute the sum of the two vectors by using the Component Method (Ax = A cosθ and Ay = A sinθ ) as well as the Triangle Method (A/Sin α = B / Sin β = C / Sin γ and C2 = A2 + B2 – 2AB Cos γ). Record the results in the Data Table.
- The magnitudes of the forces as shown in the figure are: F_1 = 80.0N, F_2 = 60.0N and F_3 = 40.0N. a) Determine the components of the force, b) the resultant force acting on the particle, and c) the direction of the resultant force.ament Chapter 05, Problem 007 There are two forces on the 1.82 kg box in the overhead view of the figure but only one is shown. For F, = 20.0 N, a = 13.5 m/s², and 0 = 21.5°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.) %3D (a) Number i+ j Units (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show WorkDetermine the magnitude of the x- component of force Q (in N) if P=96.4 N, Q = 55.2 N , 0= 55.53° and a = 49.46°.Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of the x-component. Use R if to the right, L if to the left, U if upward or D if downward. y P