Complete the following problems. List the parent genotypes, draw and fill in a Punnett square, and then list the offspring genotypes and phenotypes. 1. A homozygous dominant brown mouse is crossed with a heterozygous brown mouse (tan is the recessive color).
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- Instructions: Answer the following problem using the punett square and identify its Genotypic ratio and Phenotypic ratio. 1. A homozygous round-seeded plant (RR) is crossed with a homozygous wrinkle-seeded plant (rr). What is the phenotypic and genotypic ratio of their offspring? Genotypic Ratio Phenotypic Ratio- 2. A heterozygous green-colored pod (Gg) is crossed with a yellow-colored pod (gg). Predict the Genotypic and Phenotypic ratio of their offspring. Genotypic Ration Phenotypic Ration1:31 1 Drive For each of the problems below, please make sure to... Write a DETAILED KEY that explains all of your symbols used. Show your work on problems that ask. That means make sure that you are showing at least one Punnett square. Interpret your answer. A Punnett square alone will not suffice. Indicate which types of problems or vocabulary are difficult for you so that we can review them in discussion. Monohybrid cross: A single trait is crossed with only two variations of the allele. with 2. In humans, brown eyes are usually dominant over blue eyes. Suppose a blue-eyed man marries a brown-eyed woman whose father was blue eyed. What proportion of their children would you predict would have blue eyes? A brown-eyed man whose father was brown eyed and whose mother was blue eyed married a blue eyed woman whose father and mother were both brown-eyed. The couple has a blue-eyed son. For which of the individuals mentioned can you be sure 3. of the genotypes? What are their genotypes?…Dihybrid Cross Problem Set Problem 13: AaBb dihybrid cross involving epistasis. Two unlinked loci effect mouse hair color. AA or Aa mice are agouti. Mice with genotype aa are albino because all pigment production is blocked. regardless of the phenotype at the second locus. At the second locus, the B allele (agouti coat) is dominant to the b allele (black coat). What would be the result of a cross between two agouti mice of genotype AaBb? A. 4 agouti: 4 black: 8 albino B. 9 agouti: 3 black: 3 albino: 1 grey C. 9 agouti: 3 black: 4 albino D. 8 agouti: 4 black: 4 albino
- Drosohpila Punnet Square of Crosses. I need results of F1 & F2 generation using Punnett Squares for: Make Punnet Squares of the following crosses •Drosophila Female wildtype cross Male White-eye •Drosophila Male wildtype cross Female White-eye •Drosophila Female Wild Type cross Male Scarlet Eye •Drosophila Male Wild Type cross Female Scarlet Eye Also, Which allele is heterozygous and which is homozygous, & which is dominant and which is recessive?Solve and show your solutions for this problem. Short hair (S) in rabbits is dominant over long hair (s). The following crosses are carried out, producing the progeny shown. Give all possible genotypes of the parents in each cross.The following table summarises the results of the 2022-2023 Drosophila three-point cross involving the loci white eyes (w), miniature wings (m) and singed bristles (sn). The data is also available in the Excel file 'Drosophila Counts 2022-2023'. We strongly recommend working in Excel during this exercise.Phenotype Count+ + + 584w m sn 324w + + 227+ m sn 150+ m + 134w + sn 196 + + sn 134 w m + 92The aim of today's tutorial is to use the above data to establish the genetic map for these three loci. We have been told that all three loci are on the X chromosome; however, as scientists, we shouldn't simply take someone else's word for it - we need to test whether our data does, in fact, indicate linkage.As a first step, we will therefore conduct a chi-square test in order to test our data against the null hypothesis of independent assortment (i.e., "no…
- be holding online office hours Tuesday morning. Background to Problems 1 and 2. When a fly (Drosophila) strain with round, brown eyes was crossed to a different strain with kidney-shaped, red eyes, all F1 flies had eyes that were round and red. When these Fi flies were test crossed (i.e., mated to a suitable test strain), there were four distinct eye phenotypes observed in the F2, all at approximately the same frequency (i.e., ~ 25% each), namely: 1) round & red; 2) round & brown; 3) kidney-shaped & red; and 4) kidney-shaped & brown. 1) How many different genes (each with two alleles) control the eye phenotype in this example? 2) What was the phenotype of the test strain flies?Problem Set: Non-Mendelian Genetics 1. In "Four o' Clock "plants, it's flower color is incompletely dominant. The red flowers are homozygous dominant, the white flowers are homozygous recessive, and the pink flowers are heterozygous. Show genetic crosses between the following Four O'clock parents, using the Punnett squares provided and indicate the genotypic and phenotypic % below: A. Red x white Genotypic %: Phenotypic %: B. White x Pink Genotypic %: Phenotypic %: C. Pink x Pink Genotypic %: Phenotypic %:B What is the genotype ratio? What is the phenotype ratio? 3. What are the expected genotype and phenotype ratios in the following genetic conditions? Use scratch paper to do the Punnett square if needed but you do not need to draw it on the worksheet. a. Monohybrid cross between 2 heterozygous individuals (Aa x Aa) Genotype ratio: 1:2:1 Phenotype ratio: 3:1 G q 8:32 a b. Dihybrid cross between 2 heterozygous individuals (AaBb x AaBb) Genotype ratio: Phenotype ratio: 4. Both Mrs. Smith and Mrs. Jones had babies the same day in the same hospital. Mrs. Smith took home a baby girl, whom she named Sharon. Mrs. Jones took home a girl, whom she named Jane. Mrs. Jones began to suspect, however, that the child had been accidentally switched with Mrs. Smith baby in the nursery. Blood test were made; Mr. Smith was type A, Mrs. Smith was type B, Mr. Jones was type A, Mrs. Jones was type A. Sharon was type O, and Jane was type. B. Had a mix-up occurred? Use scratch paper, you do not need to…
- (Problem 35a) E. W. Lindstrom crossed two corn plants with green seedlings and obtained the following progeny: 3583 green seedlings, 853 virescent-white seedlings, and 260 yellow seedlings (E. W. Lindstrom. 1921. Genetics 6:91-110). Give the genotypes for the green, virescent-white, and yellow progeny. Use A and a and B and b to denote dominant and recessive alleles for the genes involved. Please explain why, thanks in advance. A. green - A_B_ and A_bb, virescent-white - aaB_, yellow - aabb B. green - AAB_, virescent-white - aaBB, yellow - aabb C. green - AbBb, virescent-white - aaBB, yellow - aabb D. green - AABB, virescent-white - AaBb, yellow - aabb E. green - A_B_ and A_bb, virescent-white - aaBB, yellow- aaBbComplete the problem below and upload your work here. Partial credit will be considered. In corn, purple kernels (P) are dominant over yellow kernels (p) and round kernels (R) are dominant to wrinkled kernels (r). In a cross of PpRr (purple, round) with a pprr (yellow, wrinkled) plant, the following progeny were observed: Phenotype Observed Expected (O-E) (O-E)2/E Purple, Round 117 Yellow, Round 126 Purple, Wrinkled 130 Yellow, Wrinkled 127 Total=500 Fill out the expected values in the chart above and calculate the Chi-Square value for your table, look up the p value associated with the Chi-Square. How many degrees of freedom do you have in this cross? 2. What is your Chi Square value? 3. What is the p value for this cross and what does your value mean? Make sure to explain the p value clearly in a couple of sentences.Product Rule Given the following traits that the parents have, assign the letters H for hair type, E for eyelids, and L for lip color. Parent 1: Homozygous curly hair Homozygous short eyelids Homozygous pale lips (dominant) Genotypes Probability (fraction) (Parent 1) Parent 2: Heterozygous straight hair Heterozygous long eyelids Homozygous red lips (recessive) Probability (fraction) (Parent 2) Probability (fraction) 3. What is the probability (in percentage) that their child will inherit the following genotypes? Homozygous curly hair, Homozygous short eyelids, Heterozygous pale lips Probability= %